The data for the heat of fusion for the isopropyl alcohol is 3.301 kJ/mol. This data was taken from Parks and Kelly (1928). After acquiring this data, we can now calculate for the amount of heat:
(3.301 kJ/mol) x (1. 37 mol) = 4.52 kJ
Thus, the amount of heat required to completely melth 1.37 mol of solid isopropyl alcohol at its melting point (184 K) is 4.52 kJ.
