Question

A hydraulic lift is to be used to lift a 1900-kg weight by putting a weight of 25 kg on a piston with a diameter of 10 cm. Determine the diameter of the piston on which the weight is to be placed.

Answer 1

here in Hydraulic system the pressure on both sides will remain the same

$P_1 = P_2$

$\frac{F_1}{A_1} = \frac{F_2}{A_2}$

$\frac{mg}{\pi*\frac{10^2}{4}} = \frac{Mg}{\pi \frac{d^2}{4}}$

$\frac{25}{10^2} = \frac{1900}{d^2}$

$d = 87.2 cm$

so its diameter is 87.2 cm