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weqwewe [10]
3 years ago
9

A hydraulic lift is to be used to lift a 1900-kg weight by putting a weight of 25 kg on a piston with a diameter of 10 cm. Deter

mine the diameter of the piston on which the weight is to be placed.
Physics
1 answer:
Fynjy0 [20]3 years ago
6 0

here in Hydraulic system the pressure on both sides will remain the same

P_1 = P_2

\frac{F_1}{A_1} = \frac{F_2}{A_2}

\frac{mg}{\pi*\frac{10^2}{4}} = \frac{Mg}{\pi \frac{d^2}{4}}

\frac{25}{10^2} = \frac{1900}{d^2}

d = 87.2 cm

so its diameter is 87.2 cm

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Answer:

a = 3.125 [m/s^2]

Explanation:

In order to solve this problem, we must use the following equation of kinematics. But first, we have to convert the speed of 90 [km/h] to meters per second.

90\frac{km}{h}*\frac{1000m}{1km}*\frac{1h}{3600s}   \\= 25 \frac{m}{s}

v_{f} =v_{i} + (a*t)

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The temperature of water in a beaker is 45°C. What does this measurement represent
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22.5J

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