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3 years ago

Identify all the forces acting on a passenger while going through a loop.

Physics

1 answer:

shusha [124]3 years ago

8 0

Answer:

"Gravitational force and the acceleration force" are the forces that are acting on a passenger while going through a loop.

Explanation:

When the passengers reach the top of the loop, The force of the car's acceleration pushes all the passengers off the seat and towards the center of the loop. On the other hand the inertia will try to push the passengers back into the seat. The gravity as well as the acceleration will tend to push the passenger in opposite direction with approximately equal force, which will create a feeling of being mass-less or we can call it weightlessness.

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Two light bulbs are wired in series and one bulb burns out (opens.) Technician A says that the other bulb will still work. Techn

Radda [10]

Answer:

Neither technician

Explanation:

Neither technician is correct.

two bulbs are connected in series one bulb burn out

If one bulb in the series burns out then the circuit will break.

In a series circuit same current passes each resistor.

so, both the technician is incorrect bulb B will not work and current will not increase in the other bulb.

6 0

3 years ago

An air-track glider attached to a spring oscillates between the 14.0 cm mark and the 71.0 cm mark on the track. The glider compl

horsena [70]

Answer:

A = 2,8333 s

Explanation:

El periodo es definido como el tiene que toma de dar una oscilación.

En este caso realiza varias osicilacion por lo cual debemos encontrar el promedio del perdono.

T = t/n

calculemos

A = 34,0/ 12,0

A = 2,8333 s

6 0

2 years ago

Assume you are given an int variable named nElements and a two-dimensional array that has been created and assigned to a2d. Writ

Alex777 [14]

Answer:

Explained

Explanation:

public int dimension(int [][]a2d,int nElements)

{

int count = 0;

for(int i = 0;i < a2d.length ; i++)

{

count = count + a2d[i].length;

}

return count;

}

3 0

3 years ago

What is the average velocity of a car that travels 30 kilometers due wet in 0.50

rodikova [14]

Answer:

60km/hr west

Explanation:

When you are dealing with velocity you always name the direction its going in

3 0

3 years ago

A 1.20 kg water balloon will break if it experiences more than 530 N of force. Your 'friend' whips the water balloon toward you

soldi70 [24.7K]

Answer:

t = 0.029s

Explanation:

In order to calculate the interaction time at the moment of catching the ball, you take into account that the force exerted on an object is also given by the change, on time, of its linear momentum:

$F=\frac{\Delta p}{\Delta t}=m\frac{\Delta v}{\Delta t}$ (1)

m: mass of the water balloon = 1.20kg

Δv: change in the speed of the balloon = v2 - v1

v2: final speed = 0m/s (the balloon stops in my hands)

v1: initial speed = 13.0m/s

Δt: interaction time = ?

The water balloon brakes if the force is more than 530N. You solve the equation (1) for Δt and replace the values of the other parameters:

$|F|=|530N|= |m\frac{v_2-v_1}{\Delta t}|\\\\|530N|=| (1.20kg)\frac{0m/s-13.0m/s}{\Delta t}|\\\\\Delta t=0.029s$

The interaction time to avoid that the water balloon breaks is 0.029s

5 0

3 years ago