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yKpoI14uk [10]
3 years ago
10

Which of these IS an example of balanced forces? A. a book on a shelf B. air rushing out of a balloon C. rolling over and fallin

g off the bed D. a car speeding up at a constant rate
Physics
1 answer:
babunello [35]3 years ago
3 0

Forces are balanced when net force on the object is zero or the sum of all force on the object is zero.

For book kept on a shelf, the weight of the book in down direction is balanced by the normal force on the book by the shelf. hence the book kept on a shelf is an example of balanced force.

In case of air rushing out of balloon , the balloon experience a net force by the air coming out of it.

rolling over and falling off the bed , the object falls under gravity force.

a car speeding up accelerates. since it accelerates , it has net force on it.

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vivado [14]
New York because of the lady of all the people and excitement
3 0
3 years ago
Read 2 more answers
How many protons are there in any te atom
Andreyy89

Answer:

52

Explanation:

Tellurium is the element of the periodic table with atomic number 52.

The atomic number of a chemical element represents the number of atoms contained in the nucleus of the atom: therefore, this means that an atom of tellurium contains exactly 52 protons in its nucleus.

Tellurium is classified as a metalloid, having properties in between metals and non-metals, and it appears with a silver color.

4 0
3 years ago
ly charged particles are held 24 x 103m apart and then released from rest. The initial acceleration of the first particle is obs
inessss [21]

Answer:

Part a)

m_2 = 4.9 \times 10^7 kg

Part b)

q_1 = q_2 = 5312.6 C

Explanation:

Part a)

As we know that both charge particles will exert equal and opposite force on each other

so here the force on both the charges will be equal in magnitude

so we will have

F = m_1a_1 = m_2a_2

here we have

6.3 \times 10^7(7) = m_2(9)

now we have

m_2 = 4.9 \times 10^7 kg

Part b)

Now for the force between two charges we can say

F = \frac{kq_1q_2}{r^2}

now we have

(6.3 \times 10^7)(7) = \frac{(9\times 10^9)q^2}{(24\times 10^3)^2}

now we have

q_1 = q_2 = 5312.6 C

3 0
3 years ago
Solve the given parallel circuit by computing the desired quantities.
Alex Ar [27]

Hope this provides some answers    

7 0
3 years ago
Famed stunt pilot, Cleonvia Thread, pulls out rapidly from a dive. He is traveling at 222 mi/h at the bottom of his trajectory,
Simora [160]

Answer:

0.39 m/s²

Explanation:

From the question,

a = v²/r.................... Equation 1

Where v = velocity, r = radius.

Given: v = 222 mi/h = (222×0.44704) m/s = 9.83 m/s, r = 820 ft = (820×0.3048) m = 249.94 m.

Substitute thses values into equation 1

a = 9.83²/249.94

a = 96.63/249.94

a = 0.39 m/s²

Hence the  acceleration is 0.39 m/s²

8 0
3 years ago
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