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Harrizon [31]
2 years ago
10

A cart falls from a track with an acceleration of 10 m/s2 (which is always the acceleration due to gravity). If it falls for 9 s

econds before hitting the ground, what is it’s velocity at impact? (show work plz)
Physics
1 answer:
schepotkina [342]2 years ago
8 0

Answer:

90m/s

Explanation:

Given parameters:

Acceleration  = 10m/s²

Time of fall  = 9s

Unknown:

Final velocity  = ?

Solution:

We can assume that the cart falls from rest.

   Initial velocity  = 0m/s

Using

        v  = u + gt

v is the final velocity

u is the initial velocity

g is the acceleration due to gravity

t is the time

       v  = 0 + 10 x 9  = 90m/s

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An electron with charge −e and mass m moves in a circular orbit of radius r around a nucleus of charge Ze, where Z is the atomic
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Answer:

v=\sqrt{\frac{kZe^2}{mr}}

Explanation:

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F=k\frac{(e)(Ze)}{r^2}=k\frac{Ze^2}{r^2} (1)

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This electrostatic attraction provides the centripetal force that keeps the electron in circular motion, which is given by:

F=m\frac{v^2}{r} (2)

where

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v is the speed of the electron

Combining the two equations (1) and (2), we find

k\frac{Ze^2}{r^2}=m\frac{v^2}{r}

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2 years ago
Three cannons are located at the top of a cliff above a level plain. Cannon A is aimed at an angle of 25° above the horizontal a
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Answer:

The canon B hits the ground fast.

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