it will be shriviled due to the process called osmosis
Answer:

Explanation:
Hello there!
In this case, given the T-V variation, we understand it is possible to apply the Charles' law as shown below:

Thus, since we are interested in the initial temperature, we can solve for T1, plug in the volumes and use T2 in kelvins:

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Answer:
did you ever get the answer lol
Answer:
The heat required to raise the temperature of 12g of water from 16 C to 21 C is 60 cal.
Explanation:
Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
There is a direct proportional relationship between heat and temperature. The constant of proportionality depends on the substance that constitutes the body as on its mass, and is the product of the specific heat by the mass of the body. So, the equation that allows calculating heat exchanges is:
Q = c * m * ΔT
where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.
In this case, you know:
- Q=?
- c= 4.186

- m= 12 g
- ΔT=Tfinal - Tinitial= 21 °C - 16°C= 5 °C
Replacing:
Q= 4.186
*12 g *5 °C
Solving:
Q=251.16 J
Since 1 J is equal to 0.2388 cal, then the following rule of three can be applied: if 1 J is equal to 0.2388 cal, then 251.16 J to how many cal are?

cal= 59.98 ≅ 60
<u><em>The heat required to raise the temperature of 12g of water from 16 C to 21 C is 60 cal.</em></u>
Answer:
Na₂SO₃
Explanation:
We can use the <em>criss-cross method</em> to work out the formula.
1. Write the <em>symbols</em> of the anion and cation.
Na¹⁺ SO₃²⁻
2. <em>Criss-cross the numbers of the charge</em>s to become the subscripts of the other ion (see image).
3. Write the formula with the <em>new subscripts</em>.
Na₂(SO₃)₁
4. Omit all subscripts <em>that are 1.</em>
The formula becomes Na₂SO₃.