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zhuklara [117]
3 years ago
15

Read the list of elements given below. Be, Mg, Ca, Sr Which of the following about the elements is true? (5 points)

Chemistry
1 answer:
slava [35]3 years ago
4 0

Answer:

Pretty Sure Its A

Explanation:

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What is the correct name for the ionic compound Ca2P5
maks197457 [2]

Answer:

It is calcium phosphide.

Explanation:

Calcium phosphide is a salt like material that is composed of calcium and phosphorus in the ratio of 2:5. It has the appearance of red brown Crystalline salt.

It is use as rodenticide to kill rats.

It is also use in fire works.

7 0
3 years ago
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The elements that contain electrons in an F sublevel near the highest occupied energy level are referred to as?
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inner transmission levels i took the test

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Which best describes the trends in electronegativity on the periodic table?
Wittaler [7]

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My bad i didnt mean to put that carry on.

Explanation:

7 0
3 years ago
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The reaction of pyrrole with bromine forms predominantly __________. View Available Hint(s) The reaction of pyrrole with bromine
xenn [34]

Answer:

a) 2-bromopyrrole

Explanation:

Our options for this questions are:

a) 2-bromopyrrole

b) 2,3-dibromopyrrole

c) N-bromopyrrole

d) 3-bromopyrrole

To understand how the reaction works we have to start with the <u>resonance structures</u>. (Figure 1), on these structures, we will obtain a n<u>egative charge on carbon 2</u> in the pyrrole ring, therefore on this carbon we can generate an attack to an electrophile.

The second step is to check how the mechanism take place. An <u>electrophile is generated</u> by the Br_2 and FeBr_3. This electrophile can be <u>attacked</u> by the negative charge on carbon 2 producing the 2-bromopyrrole. (See figure 2).

I hope it helps!

5 0
3 years ago
How much heat is required to raise the temperature of 65.8 grams of water from 31.5ºC to 46.9ºC?
vodomira [7]

Answer: 1,013.32 cal × 4.18 J/cal = 4,235.68 J

Explanation:

1) Data:

Water ⇒ C = 1 cal/g°C

m = 65.8 g

Ti = 31.5°C

Tf = 36.9°C

Heat, Q = ?

2) Formula:

Q = mCΔT

3) Calculations:

Q = 65.8g × 1 cal/g°C × (46.9°C - 31.5°C) = 1,013.2 cal

4) You can convert from calories to Joules using the conversion factor:

1 cal = 4.18 J

⇒ 1,013.32 cal × 4.18 J/cal = 4,235.68 J

3 0
3 years ago
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