Answer:
K remains constant
Explanation:
The magnetic force does not do any work on the ion.
In fact, the magnetic force due to a magnetic field is always perpendicular to the motion of the charge itself. Keep in mind that the work done by a force is given by
where F is the magnitude of the force, d is the displacement of the particle, and is the angle between the direction of the force and the displacement. Since the magnetic force is perpendicular to the displacement of the ion, then and , so the work done is zero.
For the work-energy theorem, the work done on the ion is equal to the variation of its kinetic energy:
However, since W=0, then , which means that the kinetic energy of the ion does not change.
I believe the first one is true because a transverse wave generally looks like a right angle. The second one is also true. May I ask what Physics class you are taking, regular, honors, AP Physics 1, AP Physics 2? Also how close are you to finishing it?
Explanation:
As you can see in the picture, we want the swimmer to go on a straight line, so the speed of the water must be equal to the speed of the swimmer along the x-axis. We also know the value of v, so we can calculate the of the cosine of the angle (alpha) between Vx and V. Thanks to the fundamental relation of gioniometry (cos^2(x) + sin^2(x) = 1) we can find the sine of alpha and calculate Vy. With Vy we can calculate the time that the swimmer will use for reaching the dock: s = Vy * t => t = s/(Vy).
I'll let you do all the calculations, you just have to plug in values.
Answer:
Direction is downwards
Explanation:
This is by employing Flemings Right hand rule which says If you point your pointer finger in the direction the positive charge is moving, and then your middle finger in the direction of the magnetic field, your thumb points in the direction of the magnetic force pushing on the moving charge.
Answer:
Explanation:
Given
two holes are made with different sizes
Hole 1 is large in size and hole 2 is small
If the volume flow rate of water is same for both the hole then small hole must be below the large hole because for same flow rate, velocity of water is large while cross-sectional area is small so it compensate to give same flow for both the holes.
Now for radius apply Bernoulli's theorem at hole 1 and 2
if hole 1 is h distance below water surface then
and
Also
and
thus