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just olya [345]
1 year ago
12

What is the net work doneon the object over the distance shown?

Physics
1 answer:
GuDViN [60]1 year ago
4 0

A)F_0d

Explanation

If you graph the force on an object as a function of the position of that object, then the area under the curve will equal the work done on that object, so we need to find the area under the function to find the work

Step 1

find the area under the function.

so

Area:

\text{Area}=rec\tan gle_{green}+triangle_{gren}-triangle_{red}\begin{gathered} \text{the area of a rectangle is given by} \\ A_{rec}=lenght\cdot widht \\ \text{and} \\ \text{the area of a triangle is given by:} \\ A_{tr}=\frac{base\cdot height}{2} \end{gathered}

so

\begin{gathered} \text{Area}=rec\tan gle_{green}+triangle_{gren}-triangle_{red} \\ \text{replace} \\ \text{Area}=(F_0\cdot d)+\frac{(F_0\cdot d)}{2}-\frac{(F_0\cdot d)}{2} \\ \text{Area}=(F_0\cdot d) \\ Area=F_0d \end{gathered}

therefore, the answer is

A)F_0d

I hope this helps you

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A 0.0220 kg bullet moving horizontally at 400 m/s embeds itself into an initially stationary 0.500 kg block. (a) What is their v
nevsk [136]

Answer:

a) 16.86 m/s.

b) 15.40 m/s

c) 3.175 m/s  

Explanation:

let pi be the initial momentum of the system, pf be the final momentum of the system, m1 be the mass of the bullet and V1 be the intial velocity of the bullet, m2 be the mass of the block and V2 be the intial velocity of the block

a)  from the conservation of linear momentum:

                                          pi = pf

              m1×(V1)i + m2×(V2)i = Vf×(m1 + m2)

(0.0220)×(400) + (0.500)×(0) = Vf(0.0220 + 0.500)

                                         8.8 = 0.522×Vf

                                          Vf = 16.86 m/s

Therefore, the bullet-embedded block system will be moving with a speed of 16.86 m/s.

b)  let Vf be the final velocity of the bullet-embedded block system, Wf be the work done by friction on the system, Vi be the initial velocity that the bullet-embedded block system initially moves with.

the total work done on the system is given by:

                                Wtot = Δk = kf - ki

                                    Wf = 1/2×m×(Vi)^2 - 1/2×m×(Vf)^2

                    f×ΔxΔcos(Ф) = 1/2×m×(Vi)^2 - 1/2×m×(Vf)^2

                 m×Δx×g×μ×(-1) =  1/2×m×(Vi)^2 - 1/2×m×(Vf)^2

                        m×g×Δx×μ =  1/2(Vi)^2 - 1/2(Vf)^2

1/2(0.0220 + 0.500)(Vf)^2 = 1/2(0.0220 + 0.500)(16.86)^2 - (0.0220 +           0.500)×(9.8)×(8)×(0.30)

                     (0.261)(Vf)^2 = 86.469

                                (Vf)^2 = 237.2196

                                       Vf = 15.40 m/s

Therefore,   bullet-embedded block system will have a speed of 15.40 m/s after sliding of the friction surface.

c) let Vf be the speed of the bullet-embedded before hitting the block, Vi be the initial velocity of the block and V be the velocity of the bullet-embedded block and block system.

                              M×Vf + m×Vi = (m + M)×V  

 (0.0200 + 0.50)×(15.40) + (2)×(0) = (0.022 + 0.50 + 2)×V

                                             8.008 = 2.522×V

                                                    V = 3.175 m/s  

  Therefore, the bullet-embedded block and block system will be moving at a speed of 3.175 m/s.

5 0
3 years ago
A long, nonconducting cylinder (radius = 6.0 mm) has a nonuniform volume charge density given by αr2, where α = 6.2 mC/m5 and r
erastovalidia [21]

Answer: 2.80 N/C

Explanation: In order to calculate the electric firld inside the solid cylinder

non conductor we have to use the Gaussian law,

∫E.ds=Q inside/ε0

E*2πrL=ρ Volume of the Gaussian surface/ε0

E*2πrL= a*r^2 π* r^2* L/ε0

E=a*r^3/(2*ε0)

E=6.2 * (0.002)^3/ (2*8.85*10^-12)= 2.80 N/C

5 0
4 years ago
. Which of the following are forces that push upward on an indoor skydiver? Choose all that apply. *
SpyIntel [72]

The forces that push upward on an indoor skydiver are lift force and air resistance.

The forces that act on a skydiver moving downwards includes, gravity due to his weight, air resistance and lift force.

The downward forces on the indoor skydiver include the following;

  • <em>gravity due to its weight</em>
  • <em>downward force due its acceleration</em>

<em />

The upward force on the indoor skydiver include the following;

  • <em>lift force</em>
  • <em>air resistance</em>

Thus, we can conclude that the forces that push upward on an indoor skydiver are lift force and air resistance.

Learn more here:brainly.com/question/8947470

7 0
3 years ago
The mass of an electron is about 9.11 × 10-31 kg. Write this as a whole number
galina1969 [7]

Answer:

1 electron has a mass of 9.1 X 10-31 kg. How many electrons n does it take to make 1 kg?

(1 e)/(9.1 X 10-31 kg) = n/(1 kg)

So, n = 1.10 X 1030 electrons

Each electron has a charge of 1.6 X 10-19 C, where C stands for Coulombs. So, the n electrons have a charge of q = ne = (1.10 X 1030 electrons) X (1.6 X 10-19 C/electron) = 1.76 X 1011 C. This is an insane charge!

The electrostatic force between two of these 1kg bundles of electrons is given by Coulomb's law:

F = k qq/r2 = (8.99 X 109)(1.76 X 1011 C)2/(1000 m)2 = 2.78 X 1026 N.

7 0
3 years ago
Read 2 more answers
If a horse gallops one meter per second how for can it travel 1 minute
Tasya [4]
SOLUTION:

1 minute = 60 seconds

1 second = 1 metre

1 × 60 = 1 × 60

60 seconds = 60 metres

1 minute = 60 metres

Therefore, the horse can gallop / travel 60 metres in 1 minute.

Hope this helps! :)
Have a lovely day! <3
8 0
4 years ago
Read 2 more answers
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