<span>let the fsh jump with initial velocity (u) in direction (angle p) with horizontal
it can cross and reach top of trajectory if its top height h = 1.5m
and horizontal distance d = (1/2) Range
--------------------------------------...
let t be top height time
at top height, vertical component of its velocity =0
vy = 0 = u sin p - gt
t = u sin p/g
h = [u sin p]*t - 0.5 g[t[^2
1.5 = u^2 sin^2 p/g - u^2 sin^2 p/2g
u^2 sin^2 p/2g = 1.5
u^2 sin^2 p = 1.5*2*9.8 = 29.4
u sin p = 5.42 m/s >>>>>>>>>>>>>>> V-component
=====================
t = HALF the time of flight
d = (1/2) Range (R) = (1/2) [2 u^2 sin p cos p/g]
1 = u^2 sin p cos p/g
u sin p * u cos p = 9.8
5.42 * u cos p = 9.8
u cos p = 1.81 m/s >>>>>>>>>>>>> H-component
check>>
u = sqrt[u^2 cos^2 p + u^2 sin^2 p] = 5.71 m/s
u < less than fish's potential jump speed 6.26 m/s
so it will able to cross</span>
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You're right, Answer C
The dust and gas accumulate to form a solar nebula, which later on creates the star and the planets.
Answer:
L= 12 light years
Explanation:
for length dilation we use the formula
![L=L_0\sqrt{1-\frac{v^2}{c^2} }](https://tex.z-dn.net/?f=L%3DL_0%5Csqrt%7B1-%5Cfrac%7Bv%5E2%7D%7Bc%5E2%7D%20%7D)
now calculating Lo
Lo = 12.5×365×24×3600×3×10^8
= 1.183×10^17 m
now putting the values of v and Lo in the above equation we get
![L=1.183\times10^{17}\sqrt{1-\frac{0.28c^2}{c^2} }](https://tex.z-dn.net/?f=L%3D1.183%5Ctimes10%5E%7B17%7D%5Csqrt%7B1-%5Cfrac%7B0.28c%5E2%7D%7Bc%5E2%7D%20%7D)
= 1.136×10^17 m
L=
m
so L= 12 light years
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