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4 years ago

Lisa can throw a rock into the air at 35 m/s how far will the rock fly into the air ?

Physics

1 answer:

zaharov [31]4 years ago

8 0

Answer: This will be based on how much strength she put into the rock when throwing it

Explanation:

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Two astronauts, connected by a massless cord of length 10 m, sit motionless in deep space. The astronaut masses are ????1 = 60 k

ohaa [14]

Answer:

Explanation:

Let masses of astronaut be m₁ = 60 kg and m₂ = 100 kg

m₁ is at y₁ = 0 and m₂ is at y₂ = - 10 m

We have to find center of mass .

Ycm = m₁y₁ + m₂y₂ / ( m₁ + m₂ ) ,

Ycm = m₁ x 0 + 100 x -10 / ( 60 + 100 )

= $\frac{-1000 }{160}$ m

= - 6.25 m .

center of mass y = - 6.25 m .

3 0

3 years ago

The above stress can be also approximated by a sinusoidal function (i.e. sine wave) with an average 3,811 kPa, amplitude 430 kPa

stepan [7]

Answer:

306.08 kPa

Explanation:

Given data

Average stress of first wave = 3811 kPa

amplitude of first wave ( A1 ) = 430 kPa

Frequency of first wave = 6 Hz

Determine the average stress of the second sinusoidal component in kPa

Amplitude of the additional wave (A2add) = $\frac{A1}{2}$ = 430 / 2 = 215 kPa

next we will determine the resultant amplitude of the second wave

A2 = $\sqrt{A^{2} _{1} } + A^{2} _{2add} + 2A_{1}A_{2add} Cos\alpha$

= $\sqrt{430^2+ 215^2 + 2(430*215) * cos 90}$

= $\sqrt{184900 + 46225 }$

= $\sqrt{231155}$ = 480.79

hence the average stress of the second sinusoidal component

= $\frac{2A_{2} }{\pi }$

= $\frac{2 * 480.79 }{\pi }$ = 306.08 kPa

6 0

3 years ago

Can all mixtures be separated

notsponge [240]

Yes you can do it forever

6 0

4 years ago

Read 2 more answers

Two straight wires separated by a very small distance run parallel to each other, one carrying a current of 3.0 A to the right a

Lyrx [107]

Answer:

Explanation:

I1 = 3 A right

I2 = 6.8 A left

Let the distance is r from both the wires on the same side.

The formula for the magnetic field is given by

$B =\frac{\mu _{0}}{4\pi }\frac{2i}{r}$

As the direction of current in both the wires is opposite to each other

so the net magnetic field is

B = B2 - B1

$B =\frac{\mu _{0}}{4\pi }\frac{2i_{2}}{r}-\frac{\mu _{0}}{4\pi }\frac{2i_{1}}{r}$

$B =\frac{\mu _{0}}{4\pi }\frac{2\times 6.8}{r}-\frac{\mu _{0}}{4\pi }\frac{2\times 3}{r}$

$B =\frac{\mu _{0}}{4\pi }\frac{7.6}{r}$

8 0

3 years ago

If you're swimming underwater and knock two rocks together, you will hear a very loud noise. But if your friend above the water

Svetradugi [14.3K]

Answer:

The air-water interface is an example of boundary. The transmitted portion of the initial wave energy is way smaller than the reflected portion. This makes the boundary wave hard to hear.

When both the source of the sound and your ears are located underwater, the sound is louder because the sound waves can travel directly to your ear.

Explanation:

The air-to-water sound wave transmission is inhibited because more of reflection than transmission of the wave occurs at the boundary. In the end, only about 30% of the sound wave eventually reaches underwater. For sound generated underwater, all the wave energy is transmitted directly to the observer. Sound wave travel faster in water than in air because, the molecules of water are more densely packed together, and hence can easily transmit their vibration to their neighboring molecules, when compared to air.

4 0

4 years ago