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Firdavs [7]
3 years ago
14

4. You exert 375 J to move a 45-kg object 5 m. How much force is required? (Points : 3)

Physics
1 answer:
Yuri [45]3 years ago
4 0
In physics, a force is said to do work<span> if, when acting, there is a displacement of the point of application in the direction of the force. It is calculated by the formula W = f x d. Therefore, we calculate the problem above as follows:

W = f x d
375 = f x 5
</span>f = 75 N <------SECOND OPTION
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aksik [14]
What’s the question
6 0
3 years ago
Forces that are equal in strength and opposite indirection are
Otrada [13]
Hey there! My name is Christy and I'm gladly to help you out!


The three main forces that stop moving objects are friction, gravity and wind resistance. Equal forces acting inopposite directions are called balanced forces. Balanced forcesacting on an object will not change the object's motion. When you add equal forces in opposite direction, the netforce is zero.

Hope this helped!


4 0
3 years ago
Read 2 more answers
a vector a has components a x equals -5.00 m in a y equals 9.00 meters find the magnitude and the direction of the vector
Murrr4er [49]

Answer:

The magnitude = 10.30 m

The direction of the vector proceeds at angle of 119.05°

Explanation:

Given that:

A vector \bar A has component A_x = -5 m and A_y = 9 m

The magnitude of vector  \bar A can be represented as:

\bar A  = \sqrt{A_x^2 + A_y^2}

\bar A  = \sqrt{(-5)^2 + (9)^2}

\bar A  = \sqrt{25 + 81}

\bar A  = \sqrt{106}

\bar A  = 10.30 m

If we make \bar A  an angle \theta with y- axis:

Then;   tan \theta  = \frac{A_x}{A_y}

tan \theta  = \frac{5}{9}

tan \theta  = 0.555

\theta  = tan⁻¹ (0.555)

\theta  = 29.05°

Angle with positive x-axis = 90 + \theta  

= 90° + 29.05°

= 119.05°

5 0
3 years ago
if 6000j of energy is supplid to a machine to lift a load of 300N through a vvertical height of 1M calculatework out put​
kari74 [83]

Answer:

300J

Explanation:

Work done = Force x the distance travelled in the direction of the force

=300 x 1

=300J

8 0
3 years ago
a camcorder has a power rating of 19 watts. If the output voltage from its battery is 5 volts, what current does it use
Mama L [17]
3.8 amperes
work: 19w/5v=3.8amps
8 0
3 years ago
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