1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
NARA [144]
3 years ago
5

How can energy crisis be aberted?​

Physics
1 answer:
omeli [17]3 years ago
6 0

Answer:

Try and depend more on renewable energy sources. Use products that are more energy efficient. Make use of lighting control measures. Maintain climate change

You might be interested in
What is the speed of an electron traveling 32 cm in 2 ns?
abruzzese [7]

Answer:

Speed, v=1.6\times 10^8\ m/s

Explanation:

Given that,

Distance covered by the electron, d = 32 cm = 0.32 m

Time, t = 2 ns

We need to find the speed of an electron. Speed is equal to distance covered divided by time. So,

v=\dfrac{0.32}{2\times 10^{-9}}\\\\v=1.6\times 10^8\ m/s

So, the speed of the electron is 1.6\times 10^8\ m/s.

6 0
3 years ago
A 50.0-kg child stands at the rim of a merry-go-round of radius 2.00 m, rotating in such a way that it makes one revolution in 2
Vaselesa [24]

Answer:

2.01

Explanation:

First, we need to find the centripetal acceleration.

We're given that the merry go round rotates 1 revolution in 2.09 seconds. Converting to rpm, we know that it rotates 30 revolution per minute

Now this speed gotten in rpm will be converted to m/s, to ease the calculation

30 rpm = πdN/60 m/s

30 rpm = (3.142 * 4 * 30)/60

30 rpm = 377.04/60

30 rpm = 6.284 m/s

a(c) = v²/r

a(c) = 6.284²/2

a(c) = 39.49 / 2

a(c) = 19.74 m/s²

F = ma

F = 50 * 19.74

F = 987 N

Also, Normal Force, F(n) =

F(n) = mg

F(n) = 50 * 9.81

F(n) = 490.5

We then use this to find the coefficient of static friction, μ

μ = F/F(n)

μ = 987 / 490.5

μ = 2.01

7 0
3 years ago
A 0.27 kg rock is projected from the edge of the top of a building with an initial velocity of 11.7 m/s at an angle 58◦ above th
tester [92]

Incomplete question.The complete question is

A 0.27 kg rock is projected from the edge of  the top of a building with an initial velocity of  11.7 m/s at an angle 58  above the horizontal. Due to gravity, the rock strikes the ground at  a horizontal distance of 15.9 m from the base  of the building.  How tall is the building? Assume the  ground is level and that the side of the building is vertical. The acceleration of gravity is  9.8 m/s

Answer:

Total height of the building =6.78 m

Explanation:

v = 11.7 m/s

Horizontal component of velocity = v x cos 58 = 11.7*cos 58 = 6.2 m/s

Total time of flight = Horizontal distance / Horizontal component of velocity = 15.9 / 6.2 = 2.56 sec.

Vertical component of velocity = v x sin 58 = 11.7 x sin 58 = 9.92 m/s

Time taken to reach maximum height = Vertical component of velocity / g = 9.92 / 9.81 = 1.01 sec.

Hence, Time taken to reach ground from maximum height = 2.56 - 1.01 = 1.55 sec.

Hence, Maximum height from ground = 0.5 x g x t^2 = 0.5 x 9.81 x 1.55^2 = 11.78 m

Maximum height from the top of building = 0.5 x 9.81 x 1.01^2 = 5 m

Hence, Total height of the building = 11.78 m - 5 m = 6.78 m

6 0
3 years ago
What are the missing coefficients needed to make this equation balanced from left to right?
12345 [234]

Explanation:

Since the equation is not given in this case, you can follow this explanation to balance it up.

A balanced chemical equation is one in which the law of conservation of matter is strictly obeyed.

According to the laws, we know that the total mass of the reacting substances must be equal to that of the product.

To do this, coefficients are usually assigned to chemical species.

In order to know the right coefficient one can use;

  • A trial by error method of inspecting and putting the appropriate coefficients in front of the formula of reactants or products.
  • A mathematical method in which simple equations are derived can be used.

learn more:

Balanced equation brainly.com/question/2612756

#learnwithBrainly

3 0
3 years ago
Em quanto tempo o um paraquedista, em queda livre, atinge a velocidade de 90 m/s?
Nikitich [7]

Responda:

9.2s

Explicação:

Dada a pergunta:

Em quanto tempo o um paraquedista, em queda livre, atinge a velocidade de 90 m / s?

Em queda livre; a aceleração de um corpo = 9,8m / s ^ 2

Portanto, quanto tempo leva para atingir uma velocidade de 90 m / s

Da primeira equação de movimento:

v = u + em

v = velocidade final; u = velocidade inicial; a = aceleração; t = tempo

90 = 0 + 9,8t

90 = 9,8t

t = 90 / 9,8

t = 9,18s = 9,2 s

3 0
4 years ago
Other questions:
  • Alexander has a mass of 70 kilograms. his apartment is on the second floor. 5 meters yo from ground level . How much work does h
    14·1 answer
  • A simple machine that is a straight slanted surface is
    15·1 answer
  • A 1.4kg ball is swung in a vertical circle with a radius of 0.8m. If the frequency is 1.5Hz, find the tension in the rope at the
    15·1 answer
  • What metric unit would you use to estimate the actual distance between Boston and New York?
    14·1 answer
  • Describe what would happen if we removed all the plants from the food chain.
    12·2 answers
  • Leukopenia is a disease in which the body has less than the normal number of white blood cells. What effect would leukopenia hav
    13·1 answer
  • What information can scientists obtian from tree rings
    6·1 answer
  • Panel A shows a ball shortly after being thrown upward. Panel B shows the same ball in an instant on its way down. Suppose air r
    13·1 answer
  • A key falls from a bridge that is 45 m above the water. It falls directly into a model boat, moving with constant velocity, that
    12·1 answer
  • Two large parallel plates are 2.0 cm apart. The strength of the electric field between them is 50.0 N/C . What is the difference
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!