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3 years ago

13

What is the output voltage from a step up transformer with 25 turns in the primary coil and 75 turns in the secondary coil if th

e input voltage was 120 V?

1 answer:

Greeley [361]3 years ago

7 0

Answer:

360 V

Explanation:

We can use the transformer equation:

$\frac{V_p}{N_p}=\frac{V_s}{N_s}$

where

$V_p$ is the primary (input) voltage

$N_p$ is the number of turns in the primary coil

$V_s$ is the secondary (output) voltage

$N_s$ is the number of turns in the secondary coil

In this problem,

$V_p = 120 V\\N_p = 25\\N_s = 75$

Substituting into the equation, we can find the output voltage:

$V_s = N_s \frac{V_p}{N_p}=(75)\frac{120}{25}=360 V$

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How old is a bone that has 12.5% of the original amount radioactive carbon 14 remaining?

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3 years ago

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3 years ago

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Answer:

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Now connect these wires in parallel to so that their equivalent resistance is R.

then

$\frac{1}{R} = \frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}$

$\frac{1}{R} = \frac{3}{44}+\frac{3}{44}+\frac{3}{44}$

$\frac{1}{R} = \frac{9}{44}$

⇒ $\frac{R}{1} = \frac{44}{9}\ohm$

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3 years ago

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Answer:

P=(2 nm, 8mn)

Explanation:

Given :

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Let q be the positive charge magnitude placed at origin.

<u>We know the distance between the two Cartesian points is given as:</u>

$d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

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$r^2=65\ nm$

$r=\sqrt{65}$

as we know that the electric field lines emerge radially outward of a positive charge so the second charge will be at equally opposite side of the given point.

assuming that the second charge is placed at (x,y) nano-meters.

Therefore,

$x=2\times 1=2\ nm$

and

$y=2\times 8=16\ nm$

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