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victus00 [196]
3 years ago
8

What would most likely happen if the power lines in a pretroleum power plant were broken

Physics
1 answer:
tatiyna3 years ago
4 0
If a power lines in a petroleum power plant were broken CUSTOMERS WOULD NOT RECEIVE ELECTRICITY.
Power lines are used in electrical power transmission to transmit electrical energy across large distances. When these lines are broken, the generating plant will not be able to send electricity across to the consumers.
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A bird flies 3.6 km due west and then 1.8 km due north. Another bird flies 1.8 km due west and 3.6 km due north. What is the ang
kondor19780726 [428]
Define unit vectors as follows:
\hat{i} is in the eastern direction.
\hat{j} is in the northern direction.

The position of the first bird is
\vec{a} = -3.6 \, \hat{i} + 1.8 \, \hat{j}

The position of the second bird is
\vec{b} = - 1.8 \, \hat{i} + 3.6 \, \hat{j}

Let θ = the angle between the net displacement vector for the two birds.
By definition,
\vec{a} . \vec{b} = |a| |b| cos\theta \\\\ \theta = cos^{-1} ( \frac{\vec{a}.\vec{b}}{|a||b|} )

\vec{a}.\vec{b} = (-3.6)(-1.8)+(3.6)(1.8) = 12.96
|a| =  \sqrt{3.24+12.96} =4.025
Similarly,
|b| = 4.025

Therefore
\theta = cos^{-1}  \frac{12.96}{4.025^{2}} =36.9^{o}

Answer:  36.9°
5 0
3 years ago
The energy delivered to the resistive coil is dissipated as heat at a rate equal to the power input of the circuit. However, not
Nuetrik [128]

Answer:

P(bat) = V²r/(R+r)²

Explanation:

Let the resistance of the coil be R

Internal resistance of the battery be r

Emf of the battery = V

Power dissipated in the internal resistance of the battery is normally given as P = I²r

where I is the current flowing in the circuit.

From Ohm's law,

V = I R(eq)

R(eq) = (R + r)

I = V/(R+r)

P = I²r

P = [V/(R+r)]²r

P = V²r/(R+r)²

Hope this Helps!!!

6 0
3 years ago
Someone pls help with only if you know correct answer!???
Roman55 [17]

Answer:

A 2.0 kg ball, A, is moving with a velocity of 5.00 m/s due west. It collides with a stationary ball, B, also with a mass of 2.0 kg. After the collision

Explanation:

5 0
2 years ago
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When bones are moved by muscles due to
77julia77 [94]
Respiratory and circulatory
6 0
3 years ago
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250 mL 0.1 M HCl solution is mixed with 250 mL
pishuonlain [190]

Answer:

The concentration of OH⁻ in the mixture is 0.05 M

Explanation:

The reaction of neutralization between HCl and NaOH is the following:

H⁺(aq) + OH⁻(aq) ⇄  H₂O(l)

The number of moles of HCl is:

n_{HCl} = C*V = 0.1 mol/L*0.250L = 0.025 moles

Similarly, the number of moles of NaOH is:

n_{NaOH} = C*V = 0.2 mol/L*0.250L = 0.05 moles

Now, from the reaction of HCl and NaOH we have the following number of moles of NaOH remaining:

n_{NaOH} = 0.05 moles - 0.025 moles = 0.025 moles

Finally, the concentration of OH⁻ in the mixture is:

C =\frac{n_{NaOH}}{V_{T}}=\frac{0.025 moles}{0.250*2 L} = 0.05 moles/L

Therefore, the concentration of OH⁻ in the mixture is 0.05 M.

I hope it helps you!

8 0
2 years ago
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