okay so you would go down to -8, then the slope would be 4/1 which means to go up four and then over one. then you have the line.
i hope this helps you!
Using the normal distribution, it is found that 0.26% of the items will either weigh less than 87 grams or more than 93 grams.
In a <em>normal distribution</em> with mean
and standard deviation
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
In this problem:
- The mean is of 90 grams, hence
.
- The standard deviation is of 1 gram, hence
.
We want to find the probability of an item <u>differing more than 3 grams from the mean</u>, hence:



The probability is P(|Z| > 3), which is 2 multiplied by the p-value of Z = -3.
- Looking at the z-table, Z = -3 has a p-value of 0.0013.
2 x 0.0013 = 0.0026
0.0026 x 100% = 0.26%
0.26% of the items will either weigh less than 87 grams or more than 93 grams.
For more on the normal distribution, you can check brainly.com/question/24663213
Answer: The required probability is 0.3456.
Step-by-step explanation:
Since we have given that
Probability of winning at any given time = 0.6
Probability of losing at any given time = 1-0.6 = 0.4
Number of total matches = 5
Number of won matches = 3
So, using "Binomial distribution", we get that

Hence, the required probability is 0.3456.
Answer:
sorry I don't know buddy but have a nice day
Step-by-step explanation:
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