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Degger [83]
2 years ago
11

The refrigerant is being recovered from an A/C system. Five minutes after the recovery process is complete, the low-side pressur

e loses the vacuum and the pressure rises above zero. This condition indicates:
Physics
1 answer:
SashulF [63]2 years ago
8 0

Answer:

The low side pressure of an A/C system losing vacuum and the pressure rising above zero indicates that there is too much refrigerant in the system.

Explanation:

Considering an A/C system, the condenser fan might be malfunctioning if the low side pressure of the air conditioner is excessive. On the other hand, it's also conceivable that the system has been overcharged with refrigerant.

Stated the scenario that the refrigerant of the system was being recovered, it is an indication that the system is merely overcharged. Even with the engine off, you will notice high pressures.

Either too much oil is present, or there is too much refrigerant in the air conditioning system. In either case, until you let some of that pressure out—ideally, a mechanic should do this—the issue won't go away on its own.

To know more about the pressure scenarios related to AC systems, refer to:

brainly.com/question/17072827

#SPJ4

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ExtremeBDS [4]

1. All the relevant resistors are in series, so the total (or equivalent) resistance is the sum of the resistances of the resistors: 20 Ω + 80 Ω + 50 Ω = 150 Ω [choice A].

2. The ammeter will read the current flowing through this circuit. We can find the ammeter reading using Ohm's law in terms of the electromotive force provided by the battery: I = ℰ/R = (30 V)(150 Ω) = 0.20 A [choice C].

3. The voltmeter will measure the potential drop across the 50 Ω resistor, i.e., the voltage at that resistor. We know from question 2 that the current flowing through the resistor is 0.20 A. So, from Ohm's law, V = IR = (0.20 A)(50 Ω) = 10. V, which will be the voltmeter reading [choice F].

4. Trick question? If the circuit becomes open, then no current will flow. Moreover, even if the voltmeter were kept as element of the circuit, voltmeters generally have a very high resistance (an ideal voltmeter has infinite resistance), so the current moving through the circuit will be negligible if not nil. In any case, the ammeter reading would be 0 A [choice B].

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2 years ago
A bolt of lightning discharges 9.7 C in 8.9 x 10^-5 s. What is the average current during the discharge?
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Answer: 1.089\times 10^5\ A

Explanation:

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Charge discharged Q=9.7\C

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Current is given as rate of change of discharge i.e.

\Rightarrow I=\dfrac{Q}{t}\\\\\Rightarrow I=\dfrac{9.7}{8.9\times 10^{-5}}\\\\\Rightarrow I=1.089\times 10^5\ A

Therefore, the average current is 1.089\times 10^5\ A

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2 years ago
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6 0
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