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Setler79 [48]
3 years ago
13

How did Rutherford’s atomic model fix the shortcomings of Thomson’s atomic model?

Chemistry
1 answer:
dedylja [7]3 years ago
7 0

<u>Plum Pudding Model(Thomson's atomic model)</u>

  • Thomson's atomic model states that an atom has a positive sphere charge with electrons embedded inside it. He compared the atom with a plum pudding,as the electrons according to him seemed like the dry fruits embedded in the spherical pudding.

<u>Rutherford's Model</u>

  • However Rutherford bombarded high energy streams of α-particles on a thin gold foil of 100 nm thickness. The  deflection produced by  the trajectory of these high energy  α-particles after interaction with the thin sheet of gold was studied by placing a screen made up of zinc sulfide around the gold foil.
  • The major observations made by Rutherford were that  a very huge fraction of α-particles passed through the gold sheet without getting deflected. Thus he concluded that the major part of an atom must be empty.
  • Very few   α-particles  got deflected minutely or at very small angles  by the gold sheet when they were bombarded against it.  Also very few particles got deflected at large angles. This made him conclude that the positive charge is concentrated in a very small region and is  not distributed uniformly.

From the above observations he gave the following postulates:

  • An atom is made up of  positively charged particles. The mass of an atom was concentrated in small region which is  named as the nucleus of an atom.
  • The  nucleus is surrounded by  electrons which are negatively charged particles which  revolve around the nucleus in a fixed circular path called as “orbits.”
  • An atom is  electrically neutral because electrons are negatively charged and the  nucleus is positively charged. The electrons are held by the nucleus due to a  strong electrostatic force.
  • Compared to the total size of an atom the size of the nucleus is very small.
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In a labratory activity the density of a sample of vanadium is determined to be 6.9g/cm^3 at room temperature. what is the perce
Snowcat [4.5K]

Answer:

c : 13%

Explanation:

Data Give:

Experimental density of vanadium = 6.9 g/cm³

percent error = ?

Solution:

Formula used to calculate % error

  % error = [experimental value -accepted value/accepted value] x 100

The reported accepted density value for vanadium = 6.11 g/cm³

Put value in the above equation

                  % error = [ 6.9 - 6.11 / 6.11 ] x 100

                  % error = [ 0.79 / 6.11 ] x 100

                  % error = [ 0.129] x 100

                  % error = 12.9

Round to the 2 significant figure

% error = 13 %

So, option c is correct            

7 0
3 years ago
The weight on an object depends on its(blank)and the(blank) of Earth.
Nonamiya [84]

Answer:

mass and height? idfk

Explanation:

ik mass is correct tho

7 0
3 years ago
List 3 ways how we know plants are alive?
adelina 88 [10]
They use natural resources like sunlight water they need soil water and sunlight to grow the stem should be pliable and firm and will have a green cast on the inside
3 0
3 years ago
Examination of the first few successive ionization energies for a given element usually reveals a large jump between two ionizat
gladu [14]

Answer:

See Explanation

Explanation:

Ionization energy refers to the energy required to remove an electron from an atom. Metals have lower ionization energy than non metals since ionization energy increases across a period.

One thing that we must have in mind is that it takes much more energy to remove an electron from an inner filled shell than it takes to remove an electron from an outermost incompletely filled shell.

Now let us consider the case of magnesium which has two outermost electrons. Between IE2 and IE3 we have now moved to an inner filled shell(IE3 refers to removal of electrons from the inner second shell) and a lot of energy is required to remove an electron from this inner filled shell, hence the jump.

For aluminium having three outermost electrons, there is a jump between IE3 and IE4 because IE4 deals with electron removal from a second inner filled shell and a lot of energy is involved in the process hence the jump.

Hence a jump occurs each time electrons are removed from an inner filled shell.

7 0
3 years ago
Look at the following balanced equation. How many atoms of oxygen (O) are present on the reactant side of the equation?
balu736 [363]

There are 6 atoms of oxygen on the reactant side of the following equation: 2Fe2O3 + 3C → 4Fe + 3CO2. Details about atoms can be found below.

<h3>How to find number of atoms?</h3>

The number of atoms of an element in a balanced equation is the amount of that element involved in the reaction.

According to this question, Iron oxide reacts with carbon to produce iron and carbon dioxide as follows:

2Fe2O3 + 3C → 4Fe + 3CO2

In this reaction, 2 × 3 atoms = 6 atoms of oxygen are present on the reactant side of the equation.

Learn more about number of atoms at: brainly.com/question/8834373

#SPJ1

4 0
2 years ago
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