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Setler79 [48]
3 years ago
13

How did Rutherford’s atomic model fix the shortcomings of Thomson’s atomic model?

Chemistry
1 answer:
dedylja [7]3 years ago
7 0

<u>Plum Pudding Model(Thomson's atomic model)</u>

  • Thomson's atomic model states that an atom has a positive sphere charge with electrons embedded inside it. He compared the atom with a plum pudding,as the electrons according to him seemed like the dry fruits embedded in the spherical pudding.

<u>Rutherford's Model</u>

  • However Rutherford bombarded high energy streams of α-particles on a thin gold foil of 100 nm thickness. The  deflection produced by  the trajectory of these high energy  α-particles after interaction with the thin sheet of gold was studied by placing a screen made up of zinc sulfide around the gold foil.
  • The major observations made by Rutherford were that  a very huge fraction of α-particles passed through the gold sheet without getting deflected. Thus he concluded that the major part of an atom must be empty.
  • Very few   α-particles  got deflected minutely or at very small angles  by the gold sheet when they were bombarded against it.  Also very few particles got deflected at large angles. This made him conclude that the positive charge is concentrated in a very small region and is  not distributed uniformly.

From the above observations he gave the following postulates:

  • An atom is made up of  positively charged particles. The mass of an atom was concentrated in small region which is  named as the nucleus of an atom.
  • The  nucleus is surrounded by  electrons which are negatively charged particles which  revolve around the nucleus in a fixed circular path called as “orbits.”
  • An atom is  electrically neutral because electrons are negatively charged and the  nucleus is positively charged. The electrons are held by the nucleus due to a  strong electrostatic force.
  • Compared to the total size of an atom the size of the nucleus is very small.
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m(Na₂Cr₂O₇) = 6,00 g.
n(Na₂Cr₂O₇) = m(Na₂Cr₂O₇) ÷ M(Na₂Cr₂O₇).
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n(O) = 0,161 mol.
N(O) = 0,161 mol · 6,022·10²³ 1/mol.
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