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Setler79 [48]
3 years ago
13

How did Rutherford’s atomic model fix the shortcomings of Thomson’s atomic model?

Chemistry
1 answer:
dedylja [7]3 years ago
7 0

<u>Plum Pudding Model(Thomson's atomic model)</u>

  • Thomson's atomic model states that an atom has a positive sphere charge with electrons embedded inside it. He compared the atom with a plum pudding,as the electrons according to him seemed like the dry fruits embedded in the spherical pudding.

<u>Rutherford's Model</u>

  • However Rutherford bombarded high energy streams of α-particles on a thin gold foil of 100 nm thickness. The  deflection produced by  the trajectory of these high energy  α-particles after interaction with the thin sheet of gold was studied by placing a screen made up of zinc sulfide around the gold foil.
  • The major observations made by Rutherford were that  a very huge fraction of α-particles passed through the gold sheet without getting deflected. Thus he concluded that the major part of an atom must be empty.
  • Very few   α-particles  got deflected minutely or at very small angles  by the gold sheet when they were bombarded against it.  Also very few particles got deflected at large angles. This made him conclude that the positive charge is concentrated in a very small region and is  not distributed uniformly.

From the above observations he gave the following postulates:

  • An atom is made up of  positively charged particles. The mass of an atom was concentrated in small region which is  named as the nucleus of an atom.
  • The  nucleus is surrounded by  electrons which are negatively charged particles which  revolve around the nucleus in a fixed circular path called as “orbits.”
  • An atom is  electrically neutral because electrons are negatively charged and the  nucleus is positively charged. The electrons are held by the nucleus due to a  strong electrostatic force.
  • Compared to the total size of an atom the size of the nucleus is very small.
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Explanation:

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Mixtures of hydrogen and oxygen in varying concentrations can be sparked to produce water. Define mixture and compound, and then
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Explanation:

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If 7.84 × 107 J of energy is released from a fusion reaction, what amount of mass in kilograms would be lost? Recall that c = 3
katrin [286]
  

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3 0
3 years ago
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What is the resultant pressure if 1.7 mol of ideal gas at 273 K and 2.79 atm in a closed container of constant volume is heated
dedylja [7]

Answer: The resultant pressure is 3.22 atm

Explanation:

Gay-Lussac's Law: This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.

P\propto T     (At constant volume and number of moles)

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1 = initial pressure of gas  = 2.79 atm

P_2 = final pressure of gas  = ?

T_1 = initial temperature of gas  = 273K

T_2 = final temperature of gas = 315 K

\frac{2.79}{273}=\frac{P_2}{315}

P_2=3.22atm

Thus the resultant pressure is 3.22 atm

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