Answer:
The elements in__Group_ 0 of the Periodic Table are called the_noble__gases. They are generally __unreactive_. because they have a__full_outer shell of electrons. So they do not need to gain__lose_or share _electrons_ with other atoms.
Answer:
THE EMPIRICAL FORMULA FOR THE UNKNOWN COMPOUND IS C7H9O
Explanation:
The empirical formula for the unknown compound can be obtained by following the processes below:
1 . Write out the percentage composition of the individual elements in the compound
C = 75.68 %
H = 8.80 %
O = 15.52 %
2. Divide the percentage composition by the atomic masses of the elements
C = 75 .68 / 12 = 6.3066
H = 8.80 / 1 = 8.8000
O = 15.52 / 16 = 0.9700
3. Divide the individual results by the lowest values
C = 6.3066 / 0.9700 = 6.5016
H = 8.8000 / 0.9700 = 9.0722
O = 0.9700 / 0.9700 = 1
4. Round up the values to the whole number
C = 7
H = 9
O = 1
5 Write out the empirical formula for the compound
C7H90
In conclusion, the empirical formula for the unknown compound is therefore C7H9O
F.
it's the greatest electron "hogger"
as you get closet to it, the stronger the electro negitivity.
He is halogen : they don't like to gain electrons. they are already stable.
Fr and Rn
are metals as far is I can remember. they would prefer losing electrons.
Answer:
5.5 L
Explanation:
Step 1: Given data
- Initial volume (V₁): 6.5 L
- Initial pressure (P₁): 840 mmHg
- Initial temperature (T₁): 84 °C
- Final pressure (P₂): 760 mmHg (standard pressure)
- Final temperature (T₂): 273.15 K (standard temperature)
Step 2: Convert T₁ to Kelvin
We will use the following expression.
K = °C + 273.15
K = 84 °C + 273.15 = 357 K
Step 3: Calculate the final volume of the gas
We will use the combined gas law.
P₁ × V₁ / T₁ = P₂ × V₂ / T₂
V₂ = P₁ × V₁ × T₂ / T₁ × P₂
V₂ = 840 mmHg × 6.5 L × 273.15 K / 357 K × 760 mmHg = 5.5 L
Answer:
C
Explanation:
Temperature is the measure of "hotness" of a system. When temperature increases, the kinetic energy of the particles increase. So they will collide with greater energy per collision.
