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il63 [147K]
4 years ago
8

Need help in chemistry with these 10 questions please. 80 points well be given.

Chemistry
2 answers:
Kisachek [45]4 years ago
8 0

Answer:

See the attachment for the filled in chart.

Let me know if you need any other help:)

lesya [120]4 years ago
5 0

Answer:

I can't read it but the person before me is probably correct.

Explanation:

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A sample of 67 G of kno2 is dissolved to make 1 L of solution what is the molarity of the solution?
Alik [6]

Answer:

Molarity = 0.79 M

Explanation:

Given data:

Mass of KNO₂ = 67 g

Volume of solution = 1 L

Molarity of solution = ?

Solution:

First of all we will calculate the number of moles.

<em>Number of moles = mass/ molar mass</em>

Number of moles = 67 g / 85.10379 g/mol

Number of moles = 0.79 mol

Molarity:

Molarity = number of moles / volume in L

Molarity =  0.79 mol/1 L

Molarity = 0.79 M

8 0
3 years ago
KNO3(s) --&gt; K+(aq) + NO3-(aq)This reaction was carried out in a Styrofoam insulated calorimeter and the following data were r
nataly862011 [7]

Answer:

Equation correctly showing the heat of solution

KNO_3(s)+35.2 kJ \rightarrow K^+(aq) + NO_{3}^-(aq)

Explanation:

Mass of aqueous solution = m = 100 g

Specific heat of solution = c = 4.18 J/gºC

Change in temperature = \Delta T=T_f-T_i

ΔT = 21.6ºC - 30.0ºC = -8.4ºC

Heat lost by the solution = Q

Q = mc\Delta T

Q=100 g\times 4.18 J/g^oC\times (-8.4^oC)

Q = -3,511.2 J ≈ -3.51 kJ

Heat absorbed by potassium nitrate when solution in formed; Q'

Q' = -Q = 3.51 kJ

Moles of potassium nitrate , n= \frac{10.1 g}{101 g/mol}=0.1 mol

KNO_3(s)\rightarrow K^+(aq) + NO_{3}^-(aq)

The heat of solution =

\frac{Q'}{n}=\frac{3.5112 kJ}{0.1 mol}=35.1 kJ/mol

So, the equation correctly showing the heat of solution

KNO_3(s)+35.2 kJ \rightarrow K^+(aq) + NO_{3}^-(aq)

4 0
4 years ago
Which is TRUE about intermolecular
lbvjy [14]

Answer:

They are Weaker than a chemical

<h2>bond</h2>

corrected by the one in the comment section

5 0
3 years ago
An atom has no electrical charge because _____.
Mars2501 [29]
Hey there! Great question;) Answer:it is neutrally charged because it has the same number of protons(positively charged iona) and electrons(negatively charged ions) I hope this helps:)
5 0
4 years ago
What is the silver concentration in a solution prepared by mixing 250
kotegsom [21]

Answer:

0.221M

Explanation:

From the question ,

The Molarity of AgNO₂ = 0.310 M

Hence , the concentration of Ag⁺ = 0.301 M

The volume of  AgNO₂  = 250 mL

and,

The Molarity of Sodium chromate = 0.160 M

The volume of Sodium chromate =  100 mL.

As the solution is mixed the final volume becomes ,

250mL +100mL = 350mL

Now, using the formula , to find the final molarity of the mixture ,

M₁V₁ ( initial ) =  M₂V₂ ( final )

substituting the values , in the above equation ,  

0.310M  *  250ml  =  M₂ * 350ml

M₂ = 0.221M

Hence , the concentration of the silver in the final solution = 0.221M

6 0
4 years ago
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