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4 years ago

How many hydrogen atoms are present in 5.00 mg of aspartame?

1 answer:

7 0

Aspartamate is methyl ester of aspartic acid. It is used as an artificial sweetener in foods and beverages. The molecular formula of aspartamate is: C₁₄H₁₈N₂O₅. Molecular mass of aspartamate is 294.3 g/mol.

294.3 g of aspartamate contains 1 mol of aspartamate= 6.023 X 10²³ number of aspartamate molecules. So, 5 mg of aspartamate contains (5 X 6.023 X 10²³)/ (294.3 X 1000) = 1.023 X 10¹⁹ number of aspartamate molecules. Each molecule of aspartamate has 18 H-atoms, so, 5 mg i.e, 1.023 X 10¹⁹ number of aspartamate molecules contain 18 X 1.023 X 10¹⁹= 1.84 X 10²⁰ number of hydrogen atoms.

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Describe the main properties of a gas. check all that apply

vovikov84 [41]

Gases have three characteristic properties: (1) they are easy to compress, (2) they expand to fill their containers, and (3) they occupy far more space than the liquids or solids from which they form.

5 0

3 years ago

Read 2 more answers

Pipettes are used when measuring the volumes of liquids with high degree of precision. The following volumes were obtained durin

never [62]

Answer:

0.075

Explanation:

First obtain the mean of the measurement;

Mean = 10.15 + 9.95 + 9.99 + 10.02/4 = 10.03

Then obtain d^2= (mean-score)^2 for each score;

(10.15-10.03)^2 = 0.0144

(9.95-10.03)^2 = 0.0064

(9.99-10.03)^2 = 0.0016

(10.02-10.03)^2= 0.0001

∑d^2= 0.0144 + 0.0064 + 0.0016 + 0.0001

∑d^2= 0.0225

Variance = ∑d^2/N = 0.0225/4 = 0.005625

Standard deviation= √0.005625

Standard deviation= 0.075

6 0

3 years ago

The density of gold is 19.3g/cm3. What is the mass of 11.3 cm3 of gold?

Alex_Xolod [135]

Answer:

218.09g

Explanation:

the formula for density is mass/volume

you have volume so rlly what you have is 19.3g/cm3=m/11.3cm3

so mass equals density x volume

and 19.3 x 11.3 = 218.09

3 0

3 years ago

Complete the table for ion charge based upon their losing or gaining electrons in the outer shell. (Use the periodic table as ne

hodyreva [135]

Answer:

Explanation:

Group Most Likely Ionic Charge Number of Valence Electrons

I +1 1

II +2 2

III +3 3

IV +4 or -4 4

V -3 5

VI -2 6

VII -1 7

VIII 0 8

For elements in group IV and above, their ionic charge is (8-number of their valence electrons.)

5 0

3 years ago

Read 2 more answers

Oxalic Acid, a compound found in plants and vegetables such as rhubarb, has a mass percent composition of 26.7% C, 2.24% H, and

blondinia [14]

Answer:

HCO₂

Explanation:

From the information given:

The mass of the elements are:

Carbon C = 26.7 g; Hydrogen H = 2.24 g Oxygen O = 71.1 g

To determine the empirical formula;

First thing is to find the numbers of moles of each atom.

For Carbon:

$=26.7 \ g\times \dfrac{1 \ mol }{12.01 \ g} \\ \\ =2.22 \ mol \ of \ Carbon$

For Hydrogen:

$=2.24 \ g\times \dfrac{1 \ mol }{1.008 \ g} \\ \\ =2.22 \ mol \ of \ Hydrogen$

For Oxygen:

$=71.1 \ g\times \dfrac{1 \ mol }{1.008 \ g} \\ \\ =4.44 \ mol \ of \ oxygen$

Now; we use the smallest no of moles to divide the respective moles from above.

For carbon:

$\dfrac{2.22 \ mol \ of \ carbon}{2.22} =1 \ mol \ of \ carbon$

For Hydrogen:

$\dfrac{2.22 \ mol \ of \ carbon}{2.22} =1 \ mol \ of \ hydrogen$

For Oxygen:

$\dfrac{4.44 \ mol \ of \ Oxygen}{2.22} =2 \ mol \ of \ oxygen$

Thus, the empirical formula is HCO₂

4 0

3 years ago