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3 years ago

Which of the following actions will lead to a decrease in pressure?

Chemistry

2 answers:

Alex Ar [27]3 years ago

6 0

The action that would most likely lead to. Decrease in volume is decrease in temperature.

tekilochka [14]3 years ago

6 0

Answer: The correct answer is decreasing temperature.

Explanation:

The relation between pressure, temperature, volume and number of moles of gas is given by the equal known as ideal gas equation:

$PV=nRT$

or,

$P=\frac{nRT}{V}$

where,

P = Pressure of the gas

V = Volume of the gas

n = Number of moles of gas

R = Gas constant

T = Temperature of gas

From the above relation, it is visible that pressure is directly related to number of moles and temperature of the gas. So, if pressure decreases, the number of moles and temperature of the gas also decreases.

Also, pressure is inversely related to volume of the gas. So, if pressure gets decreased, the volume of the gas must increase.

And, pressure is directly related to number of collisions of the particles. Thus, if the pressure decreases, this means that number of collisions between the particles must also decrease.

Hence, the correct answer is decreasing temperature.

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Draw the addition product formed when one equivalent of hcl reacts with the following diene.

pashok25 [27]

Answer:

Major Product = 4-chloro-4-methylcyclohex-1-ene

Explanation:

Alkene are the class of organic compounds which contain one or more double bonds between two carbon atoms. Alkenes are considered most reactive among the unsaturated hydrocarbons and they undergo addition reactions due to high electron density around the double bonds.

In given question it is written that we are provided with one equivalent of HCl while, our compound contains two double bonds (diene) so in selected starting material the HCl will be added across (hydrohalogenation reaction) the substituted double bond because it will give a more stable carbocation (tertiary carbocation) during the reaction course. Hence, as shown in reaction scheme 4-chloro-4-methylcyclohex-1-ene will be the major product.

5 0

3 years ago

Imagine two solutions with the same concentration and the same boiling point, but one has benzene as the solvent and the other h

11Alexandr11 [23.1K]

Complete question:

Imagine two solutions with the same concentration and the same boiling point, but one has benzene as the solvent and the other has carbon tetrachloride as the solvent. Determine that molal concentration, m (or b), and boiling point, Tb.

benzene boiling point=80.1 Kb=2.53

carbon tetrachloride boiling point=76.8 Kb=5.03

Answer:

m = 1.32 mol/kg

Boiling point: 83.4°C

Explanation:

When a nonvolatile solute is added to a pure solvent, the boiling point of the solvent increases, a phenomenon called ebullioscopy. This happens because of the interactions between the solute and the solvent. The temperature variation (new boiling point - normal boiling point) can be calculated by:

ΔT = m*Kb*i

Where m is the molal concentration (moles o solute/mass of solvent in kg), Kb is the ebullioscopy constant of the solvent, and i is the van't Hoff factor, which indicates how much of the solute dissociates. Let's assume that i is equal in both solvents and equal to 1 (the solvent dissociates completely)

Calling the new boiling point as Tb, for benzene:

Tb - 80.1 = m*2.53*1

Tb = 2.53m + 80.1

For carbon tetrachloride:

Tb - 76.8 = m*5.03*1

Tb = 5.03m + 76.8

Because Tb and m are equal for both:

5.03m + 76.8 = 2.53m + 80.1

2.5m = 3.3

m = 1.32 mol/kg

So, substituting m in any of the equations (choosing the first):

Tb = 2.53 * 1.32 + 80.1

Tb = 83.4°C

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3 years ago

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Plssssssssssss help me

Kryger [21]

I can’t see the picture its too small

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3 years ago

Describe the reactions role in earths natural processes?

Inessa [10]

Answer:

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3 years ago

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Mumz [18]

The answer is the third one because density is mass divided by volume so 80 divided by 10 is 8

6 0

2 years ago

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