Answer:
All of alpha-ketoglutarate formed in the citric acid cycle would contain the radioactive 
while none of succinate would contain , and all of carbon dioxide released would contain .
Explanation:
When oxaloacetate in the citric acid cycle is labeled with in carboxyl carbon atom which is farthest from keto group, alpha ketoglutarate formed from this oxaloactetate has the full radioactive label. In the next step, the carboxylic group (that contains the ) is eliminated in the form of the release of the carbon dioxide and succinate is formed. Succinate thus will not have radioactivity. 
released had all the radioactivity.
A solid dissolves in a liquid when it mixes completely with the liquid. ... Things which dissolve are called solutes and the liquid in which they dissolve is called a solvent to form a solution
Answer:
First ionization step:
H₂SeO₄(aq) + H₂O(l) → H₃O⁺(aq) + HSeO₄⁻(aq)
Second ionization step:
HSeO₄⁻(aq) + H₂O(l) → H₃O⁺(aq) + SeO₄⁻²(aq)
Explanation:
Selenic acid is a dyprotic and a strong acid with the formula: H₂SeO₄.
When it reacts to water, it release two protons in two ionizations.
Finally it gives hydronium to the medium.
H₂SeO₄(aq) + H₂O(l) → H₃O⁺(aq) + HSeO₄⁻(aq)
HSeO₄⁻(aq) + H₂O(l) → H₃O⁺(aq) + SeO₄⁻²(aq)
<u>Given:</u>
Volume of HCl = 150 ml
Molarity of HCl = 0.10 M
<u>To determine:</u>
The # moles of HCl
<u>Explanation:</u>
The molarity of a solution is the number of moles of a solute dissolved in a given volume
In this case:
Molarity of HCl = moles of HCl/volume of the solution
moles of HCl = Molarity * volume = 0.10 moles.L-1 * 0.150 L = 0.015 moles
Ans: A)
Moles of HCl is 0.015
