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ella [17]
3 years ago
6

Alternative sources of energy include : geothermal

Physics
1 answer:
baherus [9]3 years ago
6 0

Answer:

All of the above

Explanation:

The correct answer is option E (All of the above)

All the options are alternative source of energy.

The option given are not the traditional way (energy production from coal) of extracting energy as the loss of natural resources does not take place in these source of energy.

energy extracted from wind,  solar light , hydrogen ,etc are the source of energy  the alternative source of production of energy because do not exploit the natural resources, reduce the carbon emission and energy produced by them is clean energy.

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Un móvil con velocidad inicial de 19,8km/h adquiere una aceleración constante de 2,4m/s^2. Determine la velocidad y el espacio r
nata0808 [166]

Responder:

Velocidad = 41.5m / s

Espacio recorrida = 352.5 metros

Explicación:

Dado lo siguiente:

Velocidad inicial (u) = 19.8 km / h

Aceleración (a) = 2.4m / s ^ 2

Tiempo de viaje (t) = 15 s

A.) velocidad después de 15 s

Velocidad inicial = (19.8 × 1000) m / 3600s Velocidad inicial = 19800m / 3600 = 5.5m / s

Usando la ecuación: v = u + at, donde v es la velocidad

v = 5.5 + 2.4 (15)

v = 5.5 + 36

v = 41.5m / s

Espacio recorrida:

v ^ 2 = u ^ 2 + 2aS; donde S es la distancia recorrida

41.5 ^ 2 = 5.5 ^ 2 + 2 × (2.4) × S

1722.25 = 30.25 + 4.8S

1722.25 - 30.25 = 4.8S

1692 = 4.8S S = 1692 / 4.8 S = 352.5m

8 0
3 years ago
Does the sun make Gamma rays?<br>what gives Infrared light?
Gnesinka [82]
Sun fives off both of them
4 0
4 years ago
Nobel gases share which characteristics?
Leto [7]
Full outer shell of electrons, they are colorless and odorless ,their melting and boiling points are close together which gives them very narrow liquid range
8 0
3 years ago
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Determine the velocity that a car should have while traveling around a frictionless curve of radius 100m and that is banked 20 d
alex41 [277]

Answer:

v=18.89\frac{m}{s}

Explanation:

From the free-body diagram for the car, we have that the normal force has a vertical component and a horizontal component, and this component act as the centripetal force on the car:

\sum F_x:Nsin(20^\circ)=ma_c(1)\\\sum F_y:Ncos(20^\circ)=mg(2)

Solving N from (2) and replacing in (1):

N=\frac{mg}{cos(20^\circ)}\\(\frac{mg}{cos(20^\circ)})sin(20^\circ)=ma_c\\gtan(20^\circ)=a_c

The centripetal acceleration is given by:

a_c=\frac{v^2}{r}

Replacing and solving for v:

gtan(20^\circ)=\frac{v^2}{r}\\v=\sqrt{grtan(20^\circ)}\\v=\sqrt{9.8\frac{m}{s^2}(100m)tan(20^\circ)}\\v=18.89\frac{m}{s}

4 0
4 years ago
A car travels east at 11 km/h for 3.1 hours and west at 11 km/h for 5.3 hours. What distance (in km) does it travel in this time
Verizon [17]

Answer:

45.1/3× 3.1/2 + 50.1/2× 2.1/2

=136/3. 7/2.+ 101/2× 5/2

=952/6 + 505/2

=( 952+ 1515)/6

=411.16

Explanation:

Make sure to read and go with it

4 0
3 years ago
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