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kakasveta [241]
3 years ago
11

two truckers are traveling directly away from each other at the same speed. If one trucker sounds her horn at a frequency of 206

Hz, and the other trucker hears a frequency of 189 Hz, determine the speed of the trucks. Use the speed of sound as 343 m/s. m/s
Physics
1 answer:
boyakko [2]3 years ago
3 0

Answer:

v' = 14.76 m/s

Explanation:

given,

frequency of the one truck = 206 Hz

apparent frequency ,f' = 189 Hz

speed of sound, v = 343 m/s

speed of observer (v_o)and source (v_s) = v'

now, using Doppler's effect

f' = \dfrac{v-v_o}{v+v_s}\ f

f' = \dfrac{v- v'}{v+v'}\ f

189 = \dfrac{343- v'}{343+v'}\ 206

0.9174= \dfrac{343- v'}{343+v'}

314.69 + 0.9174 v' = 343 - v'

1.9174 v' = 28.30

v' = 14.76 m/s

hence, the speed of the truck is equal to 14.76 m/s

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Rest - it is the state in which body doesn’t move from it’s place

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3. Which one of these has the most inertia?
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b. A Boeing 747 airplane

Explanation:

The Boeing 747 airplane will have the most inertia of all. Inertia is the tendency of an object to remain at rest or uniform motion.

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3 0
3 years ago
If the second harmonic of a certain string is 42 Hz, what is the fundamental frequency of the string?
sdas [7]
Data:
f_{2} = 42 Hz
n (Wave node)
V (Wave belly) 
L (Wave length)
<span>The number of bells is equal to the number of the harmonic emitted by the string.
</span>
f_{n} =  \frac{nV}{2L}

Wire 2 → 2º Harmonic → n = 2

f_{n} = \frac{nV}{2L}
f_{2} = \frac{2V}{2L} &#10;
2V =  f_{2} *2L
V =  \frac{ f_{2}*2L }{2}
V =  \frac{42*2L}{2}
V =  \frac{84L}{2}
V = 42L

Wire 1 → 1º Harmonic or Fundamental rope → n = 1


f_{n} = \frac{nV}{2L}
f_{1} = \frac{1V}{2L}
f_{1} =  \frac{V}{2L}

If, We have:
V = 42L
Soon:
f_{1} = \frac{V}{2L}
f_{1} = \frac{42L}{2L}
\boxed{f_{1} = 21 Hz}

Answer:

<span>The fundamental frequency of the string:
</span>21 Hz

7 0
3 years ago
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Consider a small frictionless puck perched at the top of a xed sphere of radius R. If the puck is given a tiny nudge so that it
MakcuM [25]

Answer:

Explanation:

Let the vertical height by which it descends be h . Let it acquire velocity of v .

1/2 mv² = mgh

v² = 2gh

As it leaves the surface of sphere , reaction force of surface  R = 0 , so

centripetal force = mg cosθ where θ is the angular displacement from the vertex .  

mv² / r = mg cosθ

(m/r )x 2gh = mg cosθ

2h / r = cosθ

cosθ = (r-h) / r

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5 0
3 years ago
You hang a heavy ball with a mass of 30 kg from a tungsten rod 2.8 m long by 1.5 mm by 2.6 mm. You measure the stretch of the ro
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Answer:

Young's modulus (Y) = 3.56×10^11 N/m^2

The speed of sound in tungsten = 6166.4 m/s

Explanation:

Young's modulus (Y) = stress/strain

Stress = force/area

Force = mg = 30×9.8 = 294 N

Area = 1.5 × 2.6 = 3.9 mm^2 = 3.9/10^6 = 3.9×10^-6 m^2

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Y = 7.54×10^7/2.12×10^-4 = 3.56×10^11 N/m^2

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v = sqrt (2×9.8×1.94×10^6)

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