Answer:
Explanation:
We shall find first the velocity of ball at the time when string breaks. Let it be v . During its fall on the ground , 1.02 m below, we use the formula
h = 1/2 gt² where t is time of fall .
1.02 = 1/2 x 9.8 x t²
t²= .2081
t = .456
During this time it travels horizontally at distance of 2.5 m with uniform velocity of v
v x .456 = 2.5
v = 5.48 m /s
centripetal acceleration
= v² / r where r is radius of the circular path
= 5.48² / .478
= 62.82 m /s²
Answer:
B
Explanation:
The nucleus is made up of protons and neutrons, and electrons float around the neucleus in the electron cloud.
Answer:
option B.
Explanation:
The correct answer is option B.
when the ball drops, the velocity of the ball before the collision is v
After the collision, the velocity of the ball is the same but in the opposite direction.
Impulse delivered to the ball and the floor, in this case, is not zero.
The magnitude of the momentum remains the same but the direction of the ball changes.
Answer: 9kgm/s
Explanation:
Given that,
Mass of ball = 3 kg
Speed by which ball moves = 3 m/s. Linear momentum of the ball = ?
Since momentum refers to the quantity of motion of the moving ball,
Linear momentum = Mass x Speed
= 3kg x 3m/s
= 9 kgm/s
Thus, the linear momentum of the ball is 9kgm/s
Answer:
Explanation:
Bulk modulus is defined as the relative change in the volume of a body produced by a unit of compressive acting uniformly over its surface:
Hence the density of the seawater at a depth of 680atm is calculated as:-
