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3 years ago

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Ms. Blanks borrows $16,000 to buy a car. She pays simple interest at an annual rate of 6% over a one year period. How much does

she pay altogether?
Formula: interest = principal x rate x time Show your work

1 answer:

Kay [80]3 years ago

7 0

16000x0.06x1= 960
16000+960= 16960

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An insurance company has a merit rating system for customers who have not filed a claim in the previous year. For each year that

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Answer:

B. Fₙ₊₁ = Fₙ - 0.15Fₙ + 5

Step-by-step explanation:

The options above are examples of recurrence relations where the present state Fₙ₊₁ is dependent on the previous state Fₙ.

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A credit of $5 is also awarded, therefore:

Fₙ - 0.15Fₙ + $5

Therefore If a customer did not file a claim in the nth year, the customer's rate in the (n + 1)th year as a function of their rate in the nth year is given by:

Fₙ₊₁ = Fₙ - 0.15Fₙ + 5

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Which set of ordered pairs does not represent a function?

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Answer:

D

Step-by-step explanation:

(9,-7) and (9,-4). it is 2 Y for 1 X

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Simplify completely: 3x+18 / 18<br><br> 1) x<br> 2) 3x<br> 3) x+6 / 6<br> 4) x+18 / 6 ...?

drek231 [11]

3(x + 6)/18

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3 years ago

10 normal six sided dice are thrown.Find the probability of obtaining at least 8 failuresif a success is 5 or 6.

erastova [34]

Answer:

0.2992 = 29.92% probability of obtaining at least 8 failures.

Step-by-step explanation:

For each dice, there are only two possible outcomes. Either a failure is obtained, or a success is obtained. Trials are independent, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A success is 5 or 6.

A dice has 6 sides, numbered 1 to 6. Since a success is 5 or 6, the other 4 numbers are failures, and the probability of failure is:

$p = \frac{4}{6} = 0.6667$

10 normal six sided dice are thrown.

This means that $n = 10$

Find the probability of obtaining at least 8 failures.

This is:

$P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10)$

So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{10,8}.(0.6667)^{8}.(0.3333)^{2} = 0.1951$

$P(X = 9) = C_{10,9}.(0.6667)^{9}.(0.3333)^{1} = 0.0867$

$P(X = 10) = C_{10,10}.(0.6667)^{10}.(0.3333)^{0} = 0.0174$

Then

$P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) = 0.1951 + 0.0867 + 0.0174 = 0.2992$

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Dmitriy789 [7]

The answer is d its decreasing

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3 years ago