Assuming that there are plus signs between the 6, 2, and 9 the answer is 21x+20
We have to solve x in terms of a, b and c:
a x - 3 b = c
a x - 3 b + 3 b = c + 3 b
a x = c + 3 b
x = ( c + 3 b ) : a
Answer:
4 ) ( c + 3 b ) / a
Option B.
5x−2)(4x^2−3x−2)
=(5x+−2)(4x^2+−3x+−2)
=(5x)(4x^2)+(5x)(−3x)+(5x)(−2)+(−2)(4x^2)+(−2)(−3x)+(−2)(−2)
=20x^3−15x^2−10x−8x^2+6x+4
=20x^3−23x^2−4x+4
Answer:
The probability that the proportion of freshmen in the sample of 150 who plan to major in a STEM discipline is between 0.29 and 0.37 is 0.3855
Step-by-step explanation:
The probability that the proportion of freshmen in the sample of 150 who plan to major in a STEM discipline is between 0.29 and 0.37 can be calculated by finding <em>z-scores</em> and subtracting P(z<z(0.29)) from P(z<z(0.37))
z-score in the binomial distribution of 28% of freshmen entering college in a recent year planned to major in a STEM discipline can be calculated using the equation:
where
- p(s) is proportion of freshmen we are interested (0.37, 0.29)
- p is the proportion found in recent year found by research group (28% or 0.28)
- N is the sample size (150)
Then z(0.37)=
≈ 2.4550 and P(z<2.4550)=0.993
z(0.29)=
≈ 0.2728 and P(z<0.2728)=0.6075
Then P(z(0.29)<z<z(0.37))=0.993-0.6075=0.3855
Answer: 1.460
Step-by-step explanation:
Given : Researchers report that on average freshman who live on campus gain 15 pounds during their first year in college.
Let
represents the population mean .
Then, the set of hypothesis will be:-


We assume that this is normal distribution.
Sample size : n = 10, which is a small sample (n<30) ,s o we use t-test.
Sample mean : 
Standard deviation : 
The test statistic for population mean for small sample is given by :-


Hence , the value of test statistic = 1.460