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Chemistry

1 answer:

Assoli18 [71]3 years ago

4 0

i think its the last one

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Consider the balanced chemical equation for the combustion of methane (CH4).

Mrac [35]

<h3>Answer:</h3>

89.6 L of O₂

<h3>Solution:</h3>

The balanced chemical equation is as,

CH₄ + 2 O₂ → CO₂ + 2 H₂O

As at STP, one mole of any gas (Ideal gas) occupies exactly 22.4 L of Volume. Therefore, According to equation,

44 g ( 1 mol) CO₂ is produced by = 44.8 L (2 mol) of O₂

So,

88 g CO₂ will be produced by = X L of O₂

Solving for X,

X = (88 g × 44.8 L) ÷ 44 g

X = 89.6 L of O₂

5 0

3 years ago

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babunello [35]

The correct answer is Chemical energy changes to mechanical energy. Chemical energy in the battery powers the mechanical fan. ON USA TEST PREP!!!!!

8 0

3 years ago

How many moles of methane are produced when 85.1 moles of carbon dioxide gas react with excess hydrogen gas?

tino4ka555 [31]

Taking into account the reaction stoichiometry, 340.0 moles of methane are produced when 85.1 moles of carbon dioxide gas react with excess hydrogen gas

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

CO₂ + 4 H₄ → CH₄ + 2 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

CO₂: 1 mole
H₄: 4 moles
CH₄: 1 mole
H₂O: 2 moles

<h3>Moles of CH₄ formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 1 mole of CO₂ form 4 moles of CH₄, 85.1 moles of CO₂ form how many moles of CH₄?

$moles of CH_{4} =\frac{85.1 moles of CO_{2}x4 moles of CH_{4} }{1 moles of CO_{2}}$