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devlian [24]
3 years ago
14

1. In Part 1 Synthesis Reactions, the product of the first reaction is Al(OH)3. The product of the second reaction is Mg(OH)2. D

escribe what you observed in each reaction. Next, consider the general AB form of a synthesis reaction. If the first set of reactants is NH4OH and KAl(SO4)2 and the second set of reactants is MgSO4 and NH4OH, is either reaction considered a synthesis reaction as labeled in the laboratory? Why or why not? Note: Mg(OH)2 and Al(OH)3 are both used commercially as antacids.
Chemistry
2 answers:
yKpoI14uk [10]3 years ago
7 0

Answer. None of the reactions asked in the question are considered as synthesis reaction.

Explanation  According to definition of synthesis reaction two of the reactants react together in order to form a single product . synthesis reaction are also known as combination reactions.

                                              A+B\rightarrow AB............(1)

  where 'A' and 'B' are the reactants where 'AB' represent the product after reaction.

In part one, the reaction in which ammonium hydroxide reacts with potassium aluminium sulfate not only to give aluminium hydroxide  but also gives ammonium sulfate , potassium hydroxide and water.

NH_{4}OH+KAl(SO_{4})_{2}\rightarrow Al(OH)_{3} +(NH_{4})_{2} SO_{4} +KOH  ....(2)

In part two,magnesium sulfate reacts with ammonium hydroxide to give not  only magnesium hydroxide  but also ammonium sulfate.

MgSO_{4}+2NH_{4}OH}\rightarrow Mg(OH)_{2} +( NH_{4})_{2}SO_{4}...(3)

as in both reaction there are more than one product which means they are not synthesis reactions.

Scorpion4ik [409]3 years ago
5 0
The general form of a synthesis reaction is A + B --> AB. So we see two reactions here, NH4OH + KAl(SO4)2 --> Al(OH)3 (with some remaing K and NH4 and SO4), and MgSO4 + NH4OH --> Mg(OH)2 (with remaining SO4 and NNH4). Also, antacids is just a colloquial version of the word "base." So for the first reaction, we wouldn't call that a synthesis reaction, as this reaction would also include forming things like KOH. It doesn't follow the simple A+B-->AB. With the second one though, it would be more likely to see it written like Mg+2 + 2OH- --> Mg(OH)2, which does follow A+B--> AB, so it is a synthesis reaction. 
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Consider a disubstituted aromatic compound. The parent name is benzene and there is a chloro and bromo substituent. Disubstitute
Marina86 [1]

Answer:The correct names for the structure are:

--> 1. 1-bromo-3-chlorobenzene.

--> 3. meta-bromochlorobenzene.

--> 6. m-bromochlorobenzene.

Explanation:

Benzene is the simplest member of the aromatic hydrocarbons. It has a ring structure consisting of six carbon and six hydrogen atoms. This equally means that a benzene can have up to six substituents. One of the chemical properties is that benzene and other members of its series undergo substitution reaction whereby one or more of its six hydrogen atoms is replaced by monoatomic reagents.

Disubstituted benzene consists of two substituents which are described based on either numerical locants or specific words for the three possible forms.

The numerical locant method are used the same naming substitutes of other hydrocarbons. From the question, the numerical locant method was derived through using the following steps:

--> the functional group is benzene

--> there are two substituents which includes bromine( written as bromo) and chlorine ( written as chloro)

--> while placing the number, it's done alphabetically ('1-bromo' comes before '3-chloro') in a clockwise manner. This is to give chorine the lowest locant number.

The second naming method for a disubstituted benzene is the the ortho-, meta-, para- (or their singel letter equivalent) nomenclature method. This is only used for benzene structures.

--> ortho or O : this is used when the substituents are close to each other in the benzene ring.

--> meta or (m) : This is used when the substituents are separated by one carbon in the benzene ring.

--> para or (p): This is used when the substituents are across each other in the benzene ring

From the question, the bromine substituent is separated from the chlorine by one carbon atom, therefore it's meta-bromochlorobenzene or m-bromochlorobenzene.

8 0
2 years ago
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s2008m [1.1K]

A) HCO3- , carbonic acic

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3 years ago
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Aleksandr [31]

Answer:

B. 10 mL of Cabr2(aq) at 35 degrees celsius

Explanation:

The colder something is the more the atoms are compressed together; atoms can't move as much. 35 degrees is the warmest option, so it makes the most sense.

6 0
2 years ago
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Sunny_sXe [5.5K]
The answer is b, least to greatest motion.

The higher the temperature a substance is, their particles have more kinetic energy and thus move faster and have a faster motion.

From the pictures, we can see that the state changes from the coldest, ice, to the least cold, water, and to the hottest, steam. Therefore, the hotter the substance it, the water molecules have a greater motion.

So your answer is b.
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