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devlian [24]
3 years ago
14

1. In Part 1 Synthesis Reactions, the product of the first reaction is Al(OH)3. The product of the second reaction is Mg(OH)2. D

escribe what you observed in each reaction. Next, consider the general AB form of a synthesis reaction. If the first set of reactants is NH4OH and KAl(SO4)2 and the second set of reactants is MgSO4 and NH4OH, is either reaction considered a synthesis reaction as labeled in the laboratory? Why or why not? Note: Mg(OH)2 and Al(OH)3 are both used commercially as antacids.
Chemistry
2 answers:
yKpoI14uk [10]3 years ago
7 0

Answer. None of the reactions asked in the question are considered as synthesis reaction.

Explanation  According to definition of synthesis reaction two of the reactants react together in order to form a single product . synthesis reaction are also known as combination reactions.

                                              A+B\rightarrow AB............(1)

  where 'A' and 'B' are the reactants where 'AB' represent the product after reaction.

In part one, the reaction in which ammonium hydroxide reacts with potassium aluminium sulfate not only to give aluminium hydroxide  but also gives ammonium sulfate , potassium hydroxide and water.

NH_{4}OH+KAl(SO_{4})_{2}\rightarrow Al(OH)_{3} +(NH_{4})_{2} SO_{4} +KOH  ....(2)

In part two,magnesium sulfate reacts with ammonium hydroxide to give not  only magnesium hydroxide  but also ammonium sulfate.

MgSO_{4}+2NH_{4}OH}\rightarrow Mg(OH)_{2} +( NH_{4})_{2}SO_{4}...(3)

as in both reaction there are more than one product which means they are not synthesis reactions.

Scorpion4ik [409]3 years ago
5 0
The general form of a synthesis reaction is A + B --> AB. So we see two reactions here, NH4OH + KAl(SO4)2 --> Al(OH)3 (with some remaing K and NH4 and SO4), and MgSO4 + NH4OH --> Mg(OH)2 (with remaining SO4 and NNH4). Also, antacids is just a colloquial version of the word "base." So for the first reaction, we wouldn't call that a synthesis reaction, as this reaction would also include forming things like KOH. It doesn't follow the simple A+B-->AB. With the second one though, it would be more likely to see it written like Mg+2 + 2OH- --> Mg(OH)2, which does follow A+B--> AB, so it is a synthesis reaction. 
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<h3>Further explanation</h3>

Given

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mol Na(Ar = 23 g/mol) :

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Na = 0.87 : 2 = 0.435

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Excess reactant : Na

Mol NaCl based on mol Cl₂, so mol NaCl :

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Mass NaCl :

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How many moles of carbon dioxide gas should be produced when 10.0 g of C2H6 are combusted at STP?
Finger [1]

Answer:

                    0.665 moles of CO₂

Explanation:

                     The balance chemical equation for the combustion of Ethane is as follow:

                            2 C₂H₆ + 7 O₂ → 4 CO₂ + 6 H₂O

Step 1: <u>Calculate moles of C₂H₆ as;</u>

                              Moles  =  Mass  /  M.Mass

Putting values,

                              Moles  =  10.0 g / 30.07 g/mol

                              Moles  =  0.3325 moles

Step 2: <u>Calculate Moles of CO₂ as;</u>

According to balance chemical equation,

                    2 moles of C₂H₆ produced  =  4 moles of CO₂

So,

             0.3325 moles of C₂H₆ will produce  =  X moles of CO₂

Solving for X,

                      X  =  0.3325 mol × 4 mol ÷ 2 mol

                      X = 0.665 moles of CO₂

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3 years ago
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