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ikadub [295]
2 years ago
14

Please help me vote you brainiest

Chemistry
1 answer:
xxTIMURxx [149]2 years ago
3 0

Answer: D

Explanation: P = W/t

W = F d

When dividing, if you have a large number over a small, you get a large number. We want a small number, so we want the opposite for our P : W/ t formula. We want a small Work and a large time.

Right off the bat, the two with the least time aren't right then.

From there, we can estimate how much work it would take using the W = F d equation. If there is a small distance, there is less work, which is what we want to achieve a small work over large time.

So, the choice with the most time and the least distance should be correct.

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c

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Which of the following reactions is the least energetic? Question 18 options: ATP + H2O → ADP + Pi ATP + H2O → AMP + PPi AMP + H
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Answer:

The correct answer is AMP+H2O→ Adenosine + pi

Explanation:

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3 years ago
Find the percent composition of C7H5N3O6
Oksana_A [137]

Finding percent composition is fairly easy. You only need to divide the mass of an element by the total mass of the compound. We can do this one element at a time.

First, let's find the total mass by using the masses of the elements given on the periodic table.

7 x 12.011 (mass of Carbon) = 84.077

5 x 1.008 (mass of Hydrogen) = 5.04

3 x 14.007 (mass of Nitrogen) = 42.021

6 x 15.999 (mass of Oxygen) = 95.994

Add all of those pieces together.

84.077 + 5.04 + 42.021 + 95.994 = 227.132 g/mol is your total. Since we also just found the mass of each individual element, the next step will be very easy.

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Hydrogen: 5.04 / 227.132 = 0.022189 ≈ 2.22 %

Nitrogen: 42.021 / 227.132 = 0.185 ≈ 18.5 %

Oxygen: 95.994 / 227.132 = 0.42263 ≈ 42.26 %

You can check your work by making sure they add up to 100%. The ones I just found add up to 99.99, which is close enough. A small difference (no more than 0.03 in my experience) is just a matter of where you rounded your numbers.

5 0
2 years ago
Enter a balanced equation for the reaction between aqueous lead (II) nitrite and aqueous lithium chloride to form solid lead (II
Dominik [7]

Answer:

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Explanation:

Let's consider the reaction between aqueous lead (II) nitrite and aqueous lithium chloride to form solid lead (II) chloride and aqueous lithium nitrite.

Pb(NO₂)₂(aq) + LiCl(aq) ⇒ PbCl₂(s) + LiNO₂(aq)

This is a double displacement reaction. We will start balancing Cl by multiplying LiCl by 2.

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Now, we have to balance Li by multiplying LiNO₂ by 2.

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