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Llana [10]
3 years ago
5

Unos amigos de 5 integrantes salen a comer, el primero pide un pollo a la brasa que cuesta S/50.00, el segundo un aeropuerto que

cuesta S/28. 50, el tercero se pide una pizza que cuesta S/20,50, el cuarto se pide un tallarín saltado que cuesta a S/10,80 y el quinto un arroz con marisco que cuesta a S/22.00. Uno de ellos paga con tarjeta de crédito de todos ellos, al pagar le incluyen el 5% del uso de tarjeta. ¿Cuánto pagó en total?
Physics
1 answer:
ser-zykov [4K]3 years ago
3 0

Respuesta:

$138.39

Explicación:

Paso 1: Calcular el total que gastaron

El total que gastaron es igual a la suma de los que gastó cada uno.

$50.00 + $28.50 + $20.50 + $10.80 + $22.00 = $131.80

Paso 2: Calcular el 5% de $131.80

$131.80 × 5% = $6.59

Paso 3: Calcular el total que pagó con la tarjeta

A los $131.80 que gastaron debe sumarle los $6.59 por el uso de tarjeta.

$131.80 + $6.59 = $138.39

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A 1.5m long string weighs 0.0020 kg. It is tensioned to 100N. A disturbance travels along it with a wavelength of 1.5m, find:a)
Zigmanuir [339]

Answer:

the propagation velocity of the wave is 274.2 m/s

Explanation:

Given;

length of the string, L = 1.5 m

mass of the string, m = 0.002 kg

Tension of the string, T = 100 N

wavelength, λ = 1.5 m

The propagation velocity of the wave is calculated as;

v = \sqrt{\frac{T}{\mu} } \\\\\mu \ is \ mass \ per \ unit \ length \ of \ the \ string\\\\\mu = \frac{0.002 \ kg}{1.5 \ m} = 0.00133 \ kg/m\\\\v = \sqrt{\frac{100}{0.00133} } \\\\v = 274.2 \ m/s

Therefore, the propagation velocity of the wave is 274.2 m/s

7 0
3 years ago
A cylindrical capacitor has an inner conductor of radius 2.7 mmmm and an outer conductor of radius 3.1 mmmm. The two conductors
Mars2501 [29]

Answer:

(A) Capacitance per unit length = 4.02 \times 10^{-10}

(B) The magnitude of charge on both conductor is Q = 4.22 \times 10^{-19} C and the sign of charge on inner conductor is +Q and the sign on outer conductor is -Q

Explanation:

Given :

Radius of inner part of conductor  (R_{1}) = 2.7 \times 10^{-3} m

Radius of outer part of conductor  (R_{2}) = 3.1 \times 10^{-3} m

The length of the capacitor (l) = 3 \times 10^{-3} m

(A)

Capacitance is purely geometrical property. It depends only on length, radius of conductor.

From the formula of cylindrical capacitor,      

     C = \frac{2\pi\epsilon_{o} l }{ln\frac{R_{2} }{R_{1} } }

Where, \epsilon_{o} = 8.85 \times 10^{-12}

But we need capacitance per unit length so,

     \frac{C}{l}  = \frac{2\pi\epsilon_{o}  }{ln\frac{R_{2} }{R_{1} } }

capacitance per unit length = \frac{6.28 \times 8.85 \times 10^{-12} }{ln(1.148)} = 4.02 \times 10^{-10}

(B)

The charge on both conductors is given by,

     Q = C \Delta V

Where, C = capacitance of cylindrical capacitor and value of C = 12.06 \times 10^{-13} F, \Delta V = 350 \times 10^{-3} V

∴ Q = 4.22 \times 10^{-19} C

The magnitude of charge on both conductor is same as above but the sign of charge is different.

Charge on inner conductor is +Q and Charge on outer conductor is -Q.

8 0
4 years ago
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