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boyakko [2]
2 years ago
7

A car speeding down the highway honks its horn, which has a frequency 392 Hz, but a resting bystander hears the frequency 440 Hz

. If the speed of sound in air is 343 m/s, how fast is the car moving
Physics
1 answer:
Natali [406]2 years ago
8 0

Answer:

37.42 m/s

Explanation:

We know that apparent frequency, \bar f is given by

\bar f=f\frac {V}{V-V_s} where f is the given frequency in this case 392, V is the speed of sound in air which is given as 343 and V_s is the speed of car which is unknown, \bar f is given as 440 Hz

440=392\times \frac {343}{343-V_s}\\343-V_s=392\times \frac {343}{440}=305.5818182\\V_s=343-305.5818182=37.41818182\approx 37.42 m/s

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Answer:

time of fall and the final velocity

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v² = u² + 2gh

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According to the first equation of motion

v = u + gt

As v is same for both the balls, the time is also same for both the balls.

So, they both have same time of fall and final velocity.

5 0
3 years ago
About 80 percent of earth volume is made up of what?
kolbaska11 [484]
About 80% of the earth's volume is made of mantle.


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Hope this helped.
4 0
3 years ago
Read 2 more answers
Help me pleaseee, it’s due today: Two people push on a large gate as shown on the view from above in the diagram. If the moment
Sladkaya [172]

Answer:

the angular acceleration of the gate is approximately 1.61  \frac{rad}{s^2}

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\sum \tau_1=I\,\alpha

In our case, both forces contribute to the same direction of torque, so we can add their torques up and get the net torque on the gate:

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Now we use this value to obtain the angular acceleration by using the given moment of inertia of the rotating gate:

\sum \tau_1=I\,\alpha\\145\,\,N\.m=(90\,\,kg\,m^2)\,\alpha\\\alpha= \frac{145}{90} \frac{rad}{s^2} = 1.61\, \frac{rad}{s^2}

4 0
3 years ago
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Licemer1 [7]
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3 years ago
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True or False: A balanced force acts on different objects, and action-
borishaifa [10]

Answer:

true

Explanation:

according to the Newton's third law

4 0
3 years ago
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