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vekshin1
4 years ago
11

What is the difference between magnetism and a magnetic field

Physics
2 answers:
kkurt [141]4 years ago
6 0
Is the physical phenomena arising from the force caused by magnet  objects that produce fields that attract or repel other objects while magnetic field is a region around the magnetic material or a moving electric charge within the force of magnetism acts 
 
Alja [10]4 years ago
5 0

Magnetism is a force that can attract "pull toward" or repel "push away" some materials. Certain elements such as cobalt, iron, and nickel. are strongly attracted by a magnetic force and are called ferromagnetic.

A magnetic field is the area of space around a magnet where magnetism is detected. The poles are where the magnetic field is the strongest. The larger the magnet, the greater its magnetic field is.

You might be interested in
how is the color of an object related to the wavelengths of light that are reflected and the wavelengths that are absorbed
Gekata [30.6K]

<u>The color of an object is related to the wavelengths of light that are reflected and the wavelengths that are absorbed because:</u>

Visible light is light that has wavelengths that can be detected by the human eye. The wavelength of visible light determines the color that the light appears. The light with the longest wavelength is red, and light with the shortest wavelength is violet.

An opaque object doesn’t allow light to pass through it. But, it reflects or absorbs the light that strike it. Some objects like the leaves reflect one or a few wavelengths of visible light and absorb the others. The reflected wavelengths are used to find the color of an object as it is seen by the human eye. Example: The leaves are in green as they reflect green light and absorb the other wavelengths light. A transparent or translucent material, such as window glass, transmits some or all of the light that strikes it. This means that the light passes through the material rather than being reflected by it. Hence, we see the material because of the transmitted light. So the wavelength of the transmitted light is used to find the color that the object appears.

4 0
4 years ago
A 495-kg dragster accelerates from rest to a final speed of 105 m/s in 395 m, during which it encounters an average frictional f
drek231 [11]

Answer:

Explanation:

According to energy conservation which states that the workdone is equal to change in the system

Workdone = change in kinetic energy + (frictional force * distance)

Workdone = ΔK + fd

Workdone = kf-Ki + fd

Workdone = = 1/2(m(v-u)^2) + fd

Given

Mass m = 495kg

final velocity v = 105m/s

initial velocity = 0m/s

Force f= 1400N

distance d = 395m

Substitute

Workdone = 1/2(495(105-0)^2) + 1400(395)

Workdone = 2,728,687.5+553000

Workdone = 3,281,687.5 Joules

Time = 8.2secs

Power output = Workdone/Time

Power output = 3,281,687.5/8.2

Power output = 885,766.768

Power output = 8.858 * 10^5 watts

3 0
4 years ago
Four forces act on bolt A as shown; F1 150N, F2 80N, F3 110N and F4 100N. Determine the magnitude and direction of the resultant
netineya [11]

Complete Question

The  complete question(reference (chegg)) is shown on the first uploaded image

Answer:

The magnitude of the resultant force is  F  =  199.64 \ N

The  direction of the resultant force is  \theta  =  4.1075^o from the horizontal plane

Explanation:

Generally when resolving force, if the force (F )is moving toward the angle then the resolve force will be  Fcos(\theta ) while if the force is  moving away from the angle  then the resolved force is  Fsin (\theta )

Now  from the diagram let resolve the forces to their horizontal component

    So

          \sum F_x  =  150 cos(30) + 100cos(15) -80sin (20)

          \sum F_x  =  199.128 \ N

Now  resolving these force into their vertical component can be mathematically evaluated as

         \sum  F_{y}  =  150 sin(30) - 100sin(15) -110 +80 cos(20)

         \sum  F_{y}  =  14.30

Now the resultant force is mathematically evaluated as

        F  =  \sqrt{F_x^2 + F_y^2}

substituting values

        F  =  \sqrt{199.128^2 + 14.3^2}

        F  =  199.64 \ N

The  direction of the resultant force is  evaluated as

       \theta  =  tan^{-1}[\frac{F_y}{F_x} ]

substituting values

       \theta  =  tan^{-1}[\frac{ 14.3}{199.128} ]

       \theta  =  4.1075^o from the horizontal plane

5 0
4 years ago
John runs 120 meters in 10 seconds and then runs back to where he started in another 10 seconds. Which statement is true? Rememb
atroni [7]

Answer:

B

Explanation:

<em>A. His speed is 0 m/s </em>

<em>B. His velocity is 12 m/s </em>

<em>C. His velocity is 0 m/s </em>

<em>D. His acceleration is 12 m/s</em>

Total distance traveled by John = 120 + 120 = 240 meters

Total time taken by John to cover the distance = 10 + 10 = 20 s

<em>Average speed of John = total distance traveled/total time taken</em>

      = 240/20 = 12 m/s

Hence, the average speed/velocity of John throughout the journey is 12 m/s.

The correct option is B.

4 0
3 years ago
A particle moves along the x axis. It is initially at the position 0.180 m, moving with velocity 0.060 m/s and acceleration -0.3
shusha [124]

Answer:

a

  x_2 = -2.3356

b

 v = -1.384 \ m/s

Explanation:

From the question we are told that

  The initial position of the particle is  x_1 = 0.180 \ m

  The initial  velocity of the particle is  u = 0.060  \  m/s

  The acceleration is   a = -0.380 \  m/s^2

   The time duration is  t = 3.80  \ s

Generally from kinematic equation

    v = u + at

=>  v = 0.060 + (-0.380 * 3.80)

=>  v = -1.384 \ m/s

Generally from kinematic equation

   v^2 = u^2 + 2as

Here s is the distance covered by the particle, so

   (-1.384)^2 = (0.060)^2 + 2(-0.380)* s

=>  s = -2.5156 \ m

Generally the final position of the particle is  

    x_2 = x_1 + s

=>   x_2 = 0.180 + (-2.5156)

=>   x_2 = -2.3356

6 0
3 years ago
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