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stealth61 [152]
3 years ago
8

You want to examine the hairy details of your favorite pet caterpillar, using a lens of focal length 8.9 cm 8.9 cm that you just

happen to have around. With the lens close to your eye and the animal at the lens's focal point, what angular magnification M M do you achieve? Assume your near point is at 25.0 cm.
Physics
1 answer:
Zepler [3.9K]3 years ago
4 0

Answer:

The angular magnification is M = 2.808

Explanation:

From the question we are told

           The focal length is  f = 8.9cm

          The near point is n_p = 25.0cm

The angular magnification is mathematically represented as

                          M = \frac{n_p}{f}

Substituting values

                        M = \frac{25}{8.9}

                           = 2.808

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A sailboat is traveling to the right when a gust of wind causes the boat to accelerate leftward at 2.5​​​​m​​/s2 for 4s. After t
Ber [7]

Answer:

+7.0 m/s

Explanation:

Let's take rightward as positive direction.

So in this problem we have:

a = -2.5 m/s^2 acceleration due to the wind (negative because it is leftward)

t = 4 s time interval

v = -3.0 m/s is the final velocity (negative because it is leftward)

We can use the following equation:

v = u + at

Where u is the initial velocity

We want to find u, so if we rearrange the equation we find:

u = v - at = (-3.0 m/s) - (-2.5 m/s^2)(4 s)=+7.0 m/s

and the positive sign means the initial direction was rightward.

6 0
4 years ago
In 3 seconds, a wave generator produces 15 pulses that spread over a distance of 45 centimeters. Calculate its velocity.
NemiM [27]

We don't even need to know how many pulses were produced
in those 3 seconds.

The beginning of the first pulse took 3 seconds to travel
45 centimeters from the generator.

Its speed is    (45 cm) / (3 sec)  =  15 cm/sec.

6 0
3 years ago
Standing still, Bruce, the quarterback, gets tackled by Biff, the 90.0-kg tackle, who is traveling at 7.0 m/s. Upon collision, B
tatyana61 [14]

\\ \sf\longmapsto \Delta P=P

\\ \sf\longmapsto m1v1=m2v2

\\ \sf\longmapsto 90(7)=m2(10)

\\ \sf\longmapsto 10m2=630

\\ \sf\longmapsto m2=\dfrac{630}{10}

\\ \sf\longmapsto m2=63kg

Bruces mass is 63kg

3 0
3 years ago
Read 2 more answers
Match the following ERA’s Question 4
inna [77]
1. Cenozoic ERA
2. Mesozoic ERA
3. Paleozoic ERA
8 0
3 years ago
Someone pls help me with this!
Lina20 [59]

Answer:

<em>F=8.87 N</em>

Explanation:

<u>Coulomb's Law </u>

The electrostatic force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between the two objects.

Written as a formula:

\displaystyle F=k\frac{q_1q_2}{d^2}

Where:

k=9\cdot 10^9\ N.m^2/c^2

q1, q2 = the objects' charge in coulomb

d= The distance between the objects  in meters

Object 1 has a charge of

q_1=-2.3\cdot 10^{-6}\ c

Object 2 has a charge of

q_2=-4.2\cdot 10^{-6}\ c

They are separated by a distance of

d = 0.099 m

Calculate the force:

\displaystyle F=9\cdot 10^9\frac{2.3\cdot 10^{-6}*4.2\cdot 10^{-6}}{0.099^2}

F=8.87 N

5 0
3 years ago
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