3. If a gas exerts 1.2 atm of pressure at a volume of 31 liters and a temperature of 360K, how many moles of the gas are in the
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Considering the combined law equation, the new temperature is -244.56 °C or 28.44 K.
<h3>Boyle's law</h3>Boyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant: if the pressure increases, the volume decreases while if the pressure decreases, the volume increases.
Mathematically, this law states that the multiplication of pressure by volume is constant:
P×V=k
<h3>Charles's law</h3>Charles's law states that the volume is directly proportional to the temperature of the gas: if the temperature increases, the volume of the gas increases while if the temperature of the gas decreases, the volume decreases.
Mathematically, Charles' law states that the ratio of volume to temperature is constant:
Gay-Lussac's law states that the pressure of a gas is directly proportional to its temperature: increasing the temperature will increase the pressure, while decreasing the temperature will decrease the pressure.
Mathematically, Gay-Lussac's law states that the ratio of pressure to temperature is constant:
Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:
Considering an initial state 1 and a final state 2, it is fulfilled:
In this case, you know:
- P1= 1 atm= 760 mmHg
- V1= 15 L
- T1= -30 °C= 243 K (being 0 °C= 273 K)
- P2= 58 mmHg
- V2= 23 L
- T2= ?
Replacing in the combined law equation:
Solving:
<u><em>T2= 28.44 K= -244.56 °C</em></u>
Finally, the new temperature is -244.56 °C or 28.44 K.
Learn more about combined law equation:
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