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lora16 [44]
3 years ago
5

Compare and contrast between nuclear fission and fusion

Chemistry
1 answer:
Drupady [299]3 years ago
8 0

Both create energy. Both require atoms.

Fission is ripping the atoms apart, fusion is forcing them together. Fission takes less energy because it's easier to rip unstable atoms apart but pushing two atoms that have similar charges together is extremely hard. Fission is currently mainstream on earth, but fusion is known for taking place within stars.

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According to kinetic-molecular theory, which of the following would not be considered an ideal gas? Check all that apply.
Vikki [24]

Answer:

are a gas at very low volumes, when gas particles are very close together

a gas at very low temperatures, when gas particles have very little kinetic energy

a gas with highly polar molecules that have very strong intermolecular forces

Explanation:

4 0
4 years ago
Read 2 more answers
Please help me with this. (: I'd appreciate it.
Soloha48 [4]

Answer:

The answer to your question is:  ΔH = -283 kJ/mol, first option

Explanation:

Reaction

                CO  +  O₂     ⇒     CO₂

ΔH = ∑H products - ∑H products

ΔH = -393.5 - (-110.5 + 0)

ΔH = -393.5 + 110.5

ΔH = -283 kJ/mol

4 0
3 years ago
What type of reaction is this?—- Large Compound=Element A+Element B
Sav [38]
This reaction is decomposition. It is the breakdown of a compound into simpler and smaller elements.
6 0
3 years ago
A sample of gas has a density of 0.53 g/L at 225 K and under a pressure of 108.8 kPa. Find the density of the gas at 345 K under
sukhopar [10]

Answer:

\rho _2=0.22g/L

Explanation:

Hello!

In this case, since we are considering an gas, which can be considered as idea, we can write the ideal gas equation in order to write it in terms of density rather than moles and volume:

PV=nRT\\\\PV=\frac{m}{MM} RT\\\\P*MM=\frac{m}{V} RT\\\\P*MM=\rho RT

Whereas MM is the molar mass of the gas. Now, since we can identify the initial and final states, we can cancel out R and MM since they remain the same:

\frac{P_1*MM}{P_2*MM} =\frac{\rho _1RT_1}{\rho _2RT_2} \\\\\frac{P_1}{P_2} =\frac{\rho _1T_1}{\rho _2T_2}

It means we can compute the final density as shown below:

\rho _2=\frac{\rho _1T_1P_2}{P_1T_2}

Now, we plug in to obtain:

\rho _2=\frac{0.53g/L*225K*68.3kPa}{345K*108.8kPa}\\\\\rho _2=0.22g/L

Regards!

8 0
3 years ago
Draw the structure of the product of each step in the following three-step synthesis. Show the formal charges, if applicable. As
Dvinal [7]

Answer:

Second step: 4-bromo-1-methyl-2-nitrobenzene.

Third step: 1.5-dibromo-2-methyl-3-nitrobenzene.

Explanation:

To solve this exercise I will use the concepts of electrophilic substitution. In these reactions, a functional group is displaced by an electrophile. In the attached image are the two main products.

5 0
3 years ago
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