Q out = Q in
Q mix = Q water
mcΔt sand + mcΔt water = mcΔt water
30.2 x 2.01 x (29.3-12.1) + 87.7 x 4.19 x (29.3-12.1)=m x 4.19 x (85.8-29.3)
1044.07+6320.36=m x 236.74
m = 31.11 g
17.86m/s
Explanation:
Given parameters:
Displacement of the ball = 50m
Time taken = 2.8s
Unknown:
Velocity of the ball = ?
Solution:
velocity is the rate of change of displacement with time
Velocity =
Velocity = = 17.86m/s
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Answer:
The sound intensity of source #2 is 38.3 W/m²
Explanation:
Given;
sound intensity of source #1, I₁ = 38.3 W/m²
sound intensity of source #2, I₂ = 2.6 dB greater than 38.3 W/m²
To determine he sound intensity of source #2 in W/m², we must convert 2.6 dB to sound intensity in W/m².
Thus, sound intensity of source #2 = 38.3 W/m² + 1.8197 x 10⁻¹² W/m² = 38.3 W/m²
Therefore, the sound intensity of source #2 is 38.3 W/m²
Answer:
the object is no longer in equilibrium .
Potential Energy= 24m * 14kg * 9.8N/kg = 3292.8J