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4 years ago

Before a star is born, the matter that will become the star exists as a _____.

2 answers:

6 0

Before a star is born, the matter that will become the star exists as a interstelar gas and dust. The stars are formed as a result of the forces:the force of gravity compresses atoms in the interstellar gas. Then the fusion reaction begins. During this fusion reaction the temperature gets extremely high and all the material evolves into a hot bright star.

xenn [34]4 years ago

6 0

a dark cool nebula......

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P.E

Vladimir79 [104]

Answer:

pagtalon?

Explanation:

because that had to be the answer

5 0

3 years ago

A 1.10-kg particle moves in the xy plane with a velocity of v with arrow = (3.80 î − 4.10 ĵ) m/s. Determine the angular momentum

nirvana33 [79]

Answer:

15.961 kgm^2 / s along negative z axis

Explanation:

m = 1.10 kg,

v = (3.80 i - 4.10 j) m/s

r = (1.50 i + 2.20 j) m

The formula for the angular momentum is given by

$\overrightarrow{L}=m (\overrightarrow{r}\times \overrightarrow{v})$

$\overrightarrow{L}=1.10 (1.50 i +2.20j)\times (3.80i-4.10j)$

$\overrightarrow{L}=-15.961 \hat{k}$

Magnitude of angular momentum is 15.961 kgm^2 / s

8 0

3 years ago

Which region is also the spinal column region?<br> vertebral<br> scapular<br> pelvic<br> sternal

NNADVOKAT [17]

Vertebral ...............

6 0

3 years ago

Read 2 more answers

Suppose a straight 1.60mm -diameter copper wire could just "float" horizontally in air because of the force due to the Earth's m

Lelechka [254]

Fb = Fg

ILB = mg

IkB = 2pi (d/2)^2 g (density copper)

I = pi (0.0016/2)^2(9.8)(8.9x10^3)/(4.2x10-5) = 4175.38 A

Hope this helps

3 0

3 years ago

A vertical tube one meter long is open at the top. It is filled with 50 cm of water. If the velocity of sound is 344 m/s, what w

emmainna [20.7K]

Answer:

The fundamental resonance frequency is 172 Hz.

Explanation:

Given;

velocity of sound, v = 344 m/s

total length of tube, Lt = 1 m = 100 cm

height of water, hw = 50 cm

length of air column, L = Lt - hw = 100 cm - 50 cm = 50 cm

For a tube open at the top (closed pipe), the fundamental wavelength is given as;

Node to anti-node (N ---- A) : L = λ / 4

λ = 4L

λ = 4 (50 cm)

λ = 200 cm = 2 m

The fundamental resonance frequency is given by;

$f_0 = \frac{v}{\lambda}\\\\f_0 = \frac{344}{2}\\\\f_0 = 172 \ Hz\\\\$

Therefore, the fundamental resonance frequency is 172 Hz.

6 0

3 years ago