Answer: Socratic
Explanation: i’m not sure but you can use Socratic it’s a good app that helps
Answers:
a)The balloon is 68 m away of the radar station
b) The direction of the balloon is towards the radar station
Explanation:
We can solve this problem with the Doppler shift equation:
(1)
Where:
is the actual frequency of the sound wave
is the "observed" frequency
is the velocity of sound
is the velocity of the observer, which is stationary
is the velocity of the source, which is the balloon
Isolating
:
(2)
(3)
(4) This is the velocity of the balloon, note the negative sign indicates the direction of motion of the balloon: It is moving towards the radar station.
Now that we have the velocity of the balloon (hence its speed, the positive value) and the time (
) given as data, we can find the distance:
(5)
(6)
Finally:
(8) This is the distance of the balloon from the radar station
Answer:
Option (D)
Explanation:
The chemical formula for normal water is H2O and the chemical formula for heavy water is D2O.
Where D is deuterium which is the isotope of hydrogen.
There are three isotopes of hydrogen.
1H1 it is called protium.
1H2 it is called deuterium.
1H3 it is called tritium.
Answer:
200 newtons
Explanation:
because the sub air that would pull the force down by all of the mass of the sub air go down by that 400 newtons there for your anwer is 200 newtons. because 600-400=200
Answer:
W = 907963.50 J = 907.96 J
Explanation:
Note: Refer to the figure attached
Now, from the figure we have similar triangles ΔAOB and ΔCOD
we have

or

Now, the work done to empty the tank can be given as:

or

or

or

or
![W = 6773.76\pi[\frac{5}{3}x^3-\frac{1}{4}x^4]^4_0](https://tex.z-dn.net/?f=W%20%3D%206773.76%5Cpi%5B%5Cfrac%7B5%7D%7B3%7Dx%5E3-%5Cfrac%7B1%7D%7B4%7Dx%5E4%5D%5E4_0%20)
or
![W = 6773.76\pi[\frac{128}{3}]](https://tex.z-dn.net/?f=W%20%3D%206773.76%5Cpi%5B%5Cfrac%7B128%7D%7B3%7D%5D%20)
or
W = 907963.50 J = 907.96 J