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2 years ago

A 750 kg car moving at 25 m/s has Kinetic Energy. To stop the car requires work. On snowy roads, the force of friction that can

Physics

1 answer:

liraira [26]2 years ago

4 0

a. By the work-energy theorem, the total work required to stop the car is equal to the change in its kinetic energy,

W = 0 - 1/2 (750 kg) (25 m/s)² ≈ -230 kJ

b. The car covers a distance x as it stops such that

W = (-725 N) x ==> x ≈ 320 m

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bagirrra123 [75]

Answer:

(a) A = 1 mm

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(c) $a_{max}=606.4 m/s^{2}/tex]Explanation:Distance moved back and forth = 2 mm Frequency, f = 124 HzSo, amplitude is the half of the distance traveled back and forth. (a) So, amplitude, A = 1 mm(b) Angular frequency, ω = 2 π f = 2 x 3.14 x 124 = 778.72 rad/s The formula for the maximum speed is given by [tex]V_{max}=\omega \times A$

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$V_{max}=0.77872 m/s$

$a_{max}=\omega ^{2}A$

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[tex]a_{max}=606.4 m/s^{2}/tex]

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