▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂☘️
The potential energy of the object depends on
- the height of the object with respect to some reference points,
- the mass of the object,
- the gravitational field the object is in.
▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂☘️
Hope it helps ~
Answer:
Negative 9.8 meters per second squared
Explanation:
The negative is for the direction (down, towards the center of the earth). Often this can be estimated as -10 m/s^2 to make calculations easier.
The velocity of the canoe is 1.7 m/s.
<h3>What is momentum?</h3>
Momentum in physics is the products of mass and velocity. Now we have to find momentum with the formula; p = mv
a) Initial momentum = (15)8 m/s + 135 = 255 Kgms-1
b) Since momentum is conserved, the total momentum after throwing the anchor is still 255 Kgms-1
c) The final velocity of the boat is obtained from;
255 Kgms-1 = (15Kg + 135 Kg) v
v = 255 Kgms-1/(15Kg + 135 Kg)
v = 1.7 m/s
Learn more about momentum: brainly.com/question/904448
b). The power depends on the RATE at which work is done.
Power = (Work or Energy) / (time)
So to calculate it, you have to know how much work is done AND how much time that takes.
In part (a), you calculated the amount of work it takes to lift the car from the ground to Point-A. But the question doesn't tell us anywhere how much time that takes. So there's NO WAY to calculate the power needed to do it.
The more power is used, the faster the car is lifted. The less power is used, the slower the car creeps up the first hill. If the people in the car have a lot of time to sit and wait, the car can be dragged from the ground up to Point-A with a very very very small power ... you could do it with a hamster on a treadmill. That would just take a long time, but it could be done if the power is small enough.
Without knowing the time, we can't calculate the power.
...
d). Kinetic energy = (1/2) · (mass) · (speed squared)
On the way up, the car stops when it reaches point-A.
On the way down, the car leaves point-A from "rest".
WHILE it's at point-A, it has <u><em>no speed</em></u>. So it has no (<em>zero</em>) kinetic energy.