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elixir [45]
3 years ago
8

Find the force of gravity between a cubic meter of water (1000kg) and the sun

Physics
1 answer:
asambeis [7]3 years ago
3 0

The question doesn't tell us WHERE the m³ of water is.  It makes a big difference, so I'll go out on a limb and assume that it's on the Earth.

Mass of the water . . . 10³ kg

Mass of the sun . . . 1.989 x 10³⁰ kg

Distance between the sun and the water . . . 1.496 x 10¹¹ meters

Newton's gravitational constant 'G' . . .  6.674 x 10⁻¹¹ m³/kg-s²

Formula for the force of gravity:

Force = G·(one mass)·(the other mass) / (distance between them)²

Force = (6.674 x 10⁻¹¹ m³/kg-s²)·(10³ kg)·(1.989 x 10³⁰ kg) / (1.496 x 10¹¹ meters)²

Force = (6.674 x 1.989) / (1.496)² · (10⁻¹¹ ⁺³ ⁺³⁰ ⁻²²) · (m³ · kg · kg) / (kg · s² · m²)

Force = (5.931) · (10⁰) · (m·kg/s²)

Force = 5.931 Newtons

I've never done this calculation before.  It's pretty cool.  It turns out that if there's something on the ground in front of you that weighs around a ton, then there's about 1.3 pounds of gravitational force pulling it toward the sun !

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A positive charge of 18nC is evenly distributed along a straight rod of length 4.0 m that is bent into a circular arc with a rad
sergey [27]

Explanation:

Formula for angle subtended at the center of the circular arc is as follows.

           \theta = \frac{S}{r}

where,   S = length of the rod

              r = radius

Putting the given values into the above formula as follows.      

                \theta = \frac{S}{r}

                             = \frac{4}{2}

                             = 2 radians (\frac{180^{o}}{\pi})

                             = 114.64^{o}

Now, we will calculate the charge density as follows.

                 \lambda = \frac{Q}{L}

                            = \frac{18 \times 10^{-9} C}{4 m}

                            = 4.5 \times 10^{-9} C/m

Now, at the center of arc we will calculate the electric field as follows.

                 E = \frac{2k \lambda Sin (\frac{\theta}{2})}{r}

                     = \frac{2(9 \times 10^{9} Nm^{2}/C^{2})(4.5 \times 10^{-9}) Sin (\frac{114.64^{o}}{2})}{2 m}

                      = 34.08 N/C

Thus, we can conclude that the magnitude of the electric eld at the center of curvature of the arc is 34.08 N/C.

5 0
3 years ago
What is the relationship between the strength of an
Anastaziya [24]

Answer:

As the number of turns in the coil increases, the strength  of the electromagnet increases.

Explanation:

When current flows through a coil the coil behaves as an electromagnet. The strength of electromagnet depend the amount of current, no of turns of coil and the core of coil.

B=μ₀ N I

μ₀ = permeability of the core

N = Number of turns of the coil

I = Current flowing through the coil

Increasing the current and number of coils increase the strength of electromagnet.

3 0
3 years ago
The energy stored in a wooden log transforms when the log is burned. Which of the following explanations BEST describes how the
Makovka662 [10]

Answer:

D. the amount of chemical energy equals the amount of heat and light energy.

Explanation:

Given that the first law of thermodynamics affirmed that energy is neither created nor destroyed however, it can be transformed from one form to another. In other words, while, during the transformation of energy, no energy is lost, the input energy is also equal to output energy.

Hence, the chemical energy stored in the log is EQUAL to the heat and light energy produced by burning.

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A grandfather clock works by swinging a pendulum back and forth with a
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Answer:

For example, a wave with a time period of 2 seconds has a frequency of

1 ÷ 2 = 0.5 Hz.

Explanation:

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