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slavikrds [6]
3 years ago
5

Complete this sentence. If mass remains the same while the volume of a substance ________, the density of the substance will____

___________. decreases, increase increases, increase increases, stay the same decreases, stay the same
Chemistry
2 answers:
zhannawk [14.2K]3 years ago
5 0
The answer would be A
Andre45 [30]3 years ago
4 0
<span> If mass remains the same while the volume of a substance increases, the density of the substance will decrease. The increase in the volume is called expansion, while the decrease in the volume is called contraction.
</span><span>The density measures how much matter (mass) there is in a given amount of space (volume).  So, if the mass stays the same and the volume increases then there is the same amount of mass ad before but in bigger volume so the density is decreased. </span>
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What is the average atomic mass (in amu) of element M?
valkas [14]
An atomic mass unit (symbolized AMU or amu) is defined as precisely 1/12 the mass of an atom of carbon-12. The carbon-12 (C-12) atom has six protons and six neutrons in its nucleus. In imprecise terms, one AMU is the average of the proton rest mass and the neutron rest mass.


4 0
3 years ago
A gas occupies 100 mL at 150. kPa. Find its volume at 200. kPa. You must show all your work to receive credit. Be sure to identi
PtichkaEL [24]

The Boyle-Mariotte's law or Boyle's law is one of the laws of gases that <u>relates the volume (V) and pressure (P) of a certain amount of gas maintained at constant temperature</u>, as follows:

PV = k

where k is a constant.

We can relate the state of a gas at a specific pressure and volume to another state in which the same gas is at different P and V since the product of both variables is equal to a constant, according to the Boyle's law, which will be the same regardless of the state of the gas. In this way,

P₁V₁ = P₂V₂

Where P₁ and V₁ is the pressure and volume of the gas to a state 1 and P₂ and V₂ is the pressure and volume of the same gas in a state 2.

In this case, in the state 1 the gas occupies a volume V₁ = 100 mL at a pressure of P₁ = 150 kPa. Then, in the state 2 the gas occupies a volume V₂ (that we must calculate through the boyle's law) at a pressure of P₂ = 200 kPa.  Substituting these values in the previous equation and clearing V₂, we have,

P₁V₁ = P₂V₂ → V₂ = \frac{P1V1}{P2}  

→ V₂ = \frac{100 mL x 150 kPa}{200 kPa}

→ V₂ = 75 mL

Then, the volume occupied by the gas at 200 kPa is V₂ = 75 mL

6 0
3 years ago
Cellular Respiration is the process of what? A. Producing oxygen at the cellular level. B. The release of energy from food. C. B
matrenka [14]

Cellular Respiration is the process of the release of energy from food. Hence, option B is correct.

<h3>What is cellular respiration?</h3>

Cellular respiration is the process by which organisms use oxygen to break down food molecules to get chemical energy for cell functions.

Through the process of cellular respiration, the energy in food is converted into energy that can be used by the body's cells. During cellular respiration, glucose and oxygen are converted into carbon dioxide and water, and the energy is transferred to ATP.

Hence, option B is correct.

Learn more about cellular respiration here:

brainly.com/question/13721588

#SPJ1

4 0
1 year ago
What type of energy is a light switch
topjm [15]

Answer:

electrical

Explanation:

With electrical energy, it's helpful to think of an on/off switch. When the switch is off, the electrical energy is stored as potential energy. When the switch is on, electrical energy is being used as kinetic energy.

7 0
3 years ago
Read 2 more answers
.950 L of .420 M H2SO4 is mixed with .900 L of .260 M KOH. What concentration of sulfuric acid remains after neutralization?
kipiarov [429]
H₂SO₄:

V=0,95L
Cm=0,420mol/L

n = CmV = 0,42mol/L * 0,95L = 0,399mol

KOH:

V=0,9L
Cm=0,26mol/L

n = CmV = 0,26mol/L * 0,9L = 0,234mol

H₂SO₄            +           2KOH ⇒ K₂SO₄ + 2H₂O
1mol                :           2mol
0,399mol         :           0,234mol
                                    limiting reagent
reamins: 0,399mol - 0,117mol = 0,282mol

n = 0,282mol
V = 0,950L + 0,900L = 1,85L

Cm = n / V = 0,282mol / 1,85L ≈ 0,152M
3 0
3 years ago
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