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Vesnalui [34]
2 years ago
11

Chemical molecules that impart positional information through their concentration gradient are called

Chemistry
2 answers:
MatroZZZ [7]2 years ago
8 0

Those molecules that we can glean information about their position via  concentration gradient are called morphogens.

<h3>What is concentration gradient?</h3>

The term concentration gradient refers to the difference in the amount of substance on two different sides. This gradient could be used to glean useful information about the molecule position.

Chemical molecules that impart positional information through their concentration gradient are called morphogens.

Learn more about concentration gradient: brainly.com/question/19589080

Dennis_Churaev [7]2 years ago
8 0

Chemical molecules that impart positional information through their concentration gradient are called morphogens.

What are morphogens?

In cells of living organisms, positional information are transported through changes in the concentration gradient of morphogens.

The presence of morphogens in a tissue helps to monitor the pattern of development of that tissue.

This chemical molecule embryology because it imparts the positional information of an embryo resulting to cells differentiating at specific positions.

Learn more about concentration gradient here:

brainly.com/question/19328396

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For the following reaction, 6.94 grams of water are mixed with excess sulfur dioxide . Assume that the percent yield of sulfurou
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<h3>Answer:</h3>

#a. Theoretical yield = 31.6 g

#b. Actual yield = 25.72 g

<h3>Explanation:</h3>

The equation for the reaction between sulfur dioxide and water to form sulfurous acid is given by the equation;

SO₂(g) + H₂O(l) → H₂SO₃(aq)

The percent yield of H₂SO₃ is 81.4%

Mass of water that reacted is 6.94 g

#a. To get the theoretical yield of H₂SO₃ we need to follow the following steps

Step 1: Calculate the moles of water

Molar mass of water = 18.02 g/mol

Mass of water = 6.94 g

But, moles = Mass/molar mass

Moles of water = 6.94 g ÷ 18.02 g/mol

                        = 0.385 mol

Step 2: Calculate moles of H₂SO₃

From the equation, the mole ratio of water to H₂SO₃ is 1 : 1

Therefore, moles of water = moles of H₂SO₃

Hence, moles of H₂SO₃ = 0.385 mol

Step 3: Theoretical mass of H₂SO₃

Mass = moles × Molar mass

Molar mass of H₂SO₃ = 82.08 g/mol

Number of moles of H₂SO₃ = 0.385 mol

Therefore;

Theoretical mass of H₂SO₃ = 0.385 mol ×  82.08 g/mol

                                             = 31.60 g

Thus, the theoretical yield of H₂SO₃ is 31.6 g

<h3>#b. Calculating the actual yield</h3>

We need to calculate the actual yield

Percent yield of H₂SO₃ is 81.4%

Theoretical yield is 31.60 g

But; Percent yield = (Actual yield/theoretical yield)×100

Therefore;

Actual yield = Percent yield × theoretical yield)÷ 100

                   = (81.4 % × 31.6) ÷ 100

                  = 25.72 g

The percent yield of H₂SO₃ is 25.72 g

6 0
3 years ago
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