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Rudik [331]
3 years ago
15

The Henry's law constant for helium gas in water at 30 °C is 3.70 × 10-4 M/atm. When the partial pressure of helium above a samp

le of water is 0.650 atm, the concentration of helium in the water is __________ M
Chemistry
1 answer:
igor_vitrenko [27]3 years ago
4 0

Answer:

The concentration of helium in the water is 2.405×10^-4 M

Explanation:

Concentration = Henry's law constant × partial pressure of helium

Henry's law constant = 3.7×10^-4 M/atm

Partial pressure of helium = 0.65 atm

Concentration = 3.7×10^-4 × 0.65 = 2.405×10^-4 M

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The formation of iodine is described by the following chemical equation:
olga nikolaevna [1]

Answer:

N2O2(g) +O2(g) ===> 2NO2(g)

Explanation:

For a nonelementary reaction, the reaction equation is described as the sum of all the steps involved. All these steps constitute the reaction mechanism. Each step in the mechanism is an elementary reaction. The rate law of the overall reaction involves the rate determining step (slowest step) in the reaction sequence.

Now look at the overall reaction 2NO(g) + O2(g) ---------> 2NO2(g)

The two steps in the mechanism are

2NO(g) --------->N2O2(g) (fast)

N2O2(g) +O2(g) -------> 2NO2(g) (slow)

Summing all the steps and cancelling out the intermediate N2O2(g), we obtain the reaction equation;

2NO(g) + O2(g) ---------> 2NO2(g)

Hence the answer.

7 0
2 years ago
Which statement describes the energy changes that occur as bonds are brokes and a chemical reaction
Leni [432]

Answer:

Energy is released when bonds are broken, and energy is absorbed when bonds are formed.

7 0
2 years ago
How does sand cause weathering?
Ivahew [28]
Sand doesn't directly cause weathering because sand is made via weathering. When rocks get weathered they become sand. But maybe when the sand and wind work together they might be able to weather some rocks
6 0
3 years ago
Read 2 more answers
Which of the following hypotheses cannot be tested using the scientific method
Arturiano [62]
I believe it's answer #3. Logically, at least.

You can test #1 through trial and error.
You can experiment #2 also through trial and error.
You cannot test #3 through trial and error, because that would be catastrophic.
You can test #4 through a survey and individual study and data collection.
7 0
3 years ago
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1.0 x 10^2 m what is the frequency of the waves
MAVERICK [17]

Answer:

f = 3 × 10⁶ Hz

Explanation:

Given data:

Wavelength of wave = 1.0 ×10² m

Frequency = ?

Solution:

Formula:

Speed of light = wavelength× frequency

Frequency = speed of light / wavelength

speed of light = 3× 10⁸ m/s

f = 3× 10⁸ m/s / 1.0 ×10² m

f = 3 × 10⁶ s⁻¹

s⁻¹ = Hz

f = 3 × 10⁶ Hz

8 0
3 years ago
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