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Rudik [331]
3 years ago
15

The Henry's law constant for helium gas in water at 30 °C is 3.70 × 10-4 M/atm. When the partial pressure of helium above a samp

le of water is 0.650 atm, the concentration of helium in the water is __________ M
Chemistry
1 answer:
igor_vitrenko [27]3 years ago
4 0

Answer:

The concentration of helium in the water is 2.405×10^-4 M

Explanation:

Concentration = Henry's law constant × partial pressure of helium

Henry's law constant = 3.7×10^-4 M/atm

Partial pressure of helium = 0.65 atm

Concentration = 3.7×10^-4 × 0.65 = 2.405×10^-4 M

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Water goes into the sky by condensation I think
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Which of the following is an example of acceleration?
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it's either B. or C.. hope this helps!

Explanation:

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It takes 2 g of chlorine to sanitize 1,000,000g of water. How much chlorine will it take to sanitize a 40,000-gallon pool? ( 1 g
dimulka [17.4K]

Answer:

0.1g (Gallon) of chlorine

Explanation:

<u>Formula</u>

1 gallon = 3.7L; the density of water is 1.0g/ml

<u>Given</u>

2g (gallon) of chlorine to sanitize = 1,000,000g (gallon) of water

<u>Solve</u>

If 2g (gallon) chlorine = 1,000,000g (gallon)

∴, ? chlorine = 40,000

The First step; set up an equation

1000000/2 = 40000/?

The Next step; divide 1 million to 2

1000000 ÷ 2 = 500000

Then, divide the result by 40000

40000 ÷ 500000 = 0.08

In the nearest unit that is 0.1

Therefore, it will take 0.1g (gallon) of chlorine to sanitize a 40,000-gallon pool.

7 0
3 years ago
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Which instrument is used to take an image from outer space that shows the depletion of the ozone layer in Earth’s atmosphere?
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Answer:

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3 0
3 years ago
A brick lies perilously close to the edge of the flat roof of a building. The roof edge is 50 ft above street level, and the bri
wel

Hey there!:

The potential energy is U =  m*g*h

Substitute 560.0 J for U = m*g*h so,  560.0 = m*g*h

g = 9.8 m/s²

50 ft in meters :

1 ft = 0.3048 m

50 ft = 50 * 0.3048 => 15.24 m

m = 560.0 / g*h

m = 560.0 / 9.8 * 15.24

m = 560.0 / 149.352

m = 3.74 kg

35 ft in m : 35 * 0.3048 => 10.668 m

The change initial  in potencial energy from point A to B is:

mg ( h1 - h2 ) = 3.74* ( 9.8 )* (15.24 - 10.668 )

=>  36.652 * ( 15.24 - 10.688 ) =

36.652 * 4.552 => 167.57 J

According to the conservation of energy

The change in potencial energy should be equal to the change in kinetic energy , so the , the change in kinetic energy is :

ΔK = 167.57 J


Hope that helps!

5 0
3 years ago
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