Question

The Henry's law constant for helium gas in water at 30 °C is 3.70 × 10-4 M/atm. When the partial pressure of helium above a sample of water is 0.650 atm, the concentration of helium in the water is __________ M

Answer 1

Answer:

The concentration of helium in the water is 2.405×10^-4 M

Explanation:

Concentration = Henry's law constant × partial pressure of helium

Henry's law constant = 3.7×10^-4 M/atm

Partial pressure of helium = 0.65 atm

Concentration = 3.7×10^-4 × 0.65 = 2.405×10^-4 M