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valentinak56 [21]
3 years ago
9

When aqueous solutions of NH4OH(aq) and CuCl2(aq) are mixed, the products are NH4Cl(aq) and Cu(OH)2(s). What is the net ionic eq

uation for this reaction
Chemistry
1 answer:
Ilia_Sergeevich [38]3 years ago
5 0

Answer:

2OH^-(aq) + Cu^2+(aq) -----> Cu(OH)2(s)

Explanation:

The net ionic equation usually shows the main ionic reaction that goes in the system. The other ions that do not participate in this net ionic equation are called spectator ions. Spectator ions do not participate in the main reaction occurring in the system.

The net ionic equation quite often result in the formation of a solid precipitate in the system such as Cu(OH)2.

The net ionic equation for this reaction is;

2OH^-(aq) + Cu^2+(aq) -----> Cu(OH)2(s)

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Which of the following types of electromagnetic waves generally has the least energy
sertanlavr [38]

Radio waves have the lowest energy, but the longest wavelength. So radio waves is the answer. Good luck on the rest and message me for more help.

7 0
3 years ago
Read 2 more answers
The Environmental Protection Agency has determined that safe drinking
dmitriy555 [2]

Answer:

b) \bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}

The confidence interval for this case is given (6.21, 6.59)

So we can conclude at 95% of confidence that the true mean for the PH concentration is between 6.21 and 6.59 moles per liter

c) Since the confidence interval not contains the value 7 we reject the hypothesis that the true mean is equal to 7. And the same result was obtained with the t test for the true mean.

Explanation:

We assume that part a is test the claim. And we can conduct the following hypothesis test:

Null hypothesis: \mu =7

Alternative hypothesis \mu \neq 7

The statistic is to check this hypothesi is given by:

t = \frac{\bar X -\mu}{\frac{s}{\sqrt{n}}}

We know the following info from the problem:

\bar X = 6.4 , s=0.5, n =30

Replacing we got:

t = \frac{6.4-7}{\frac{0.5}{\sqrt{30}}}= -6.573

And the p value would be:

p_v= 2*P(Z

Since the p value is very low compared to the significance assumed of 0.05 we have enough evidence to reject the null hypothesis that the true mean is equal to 7 moles/liter

Part b

The confidence interval is given by:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}

The confidence interval for this case is given (6.21, 6.59)

So we can conclude at 95% of confidence that the true mean for the PH concentration is between 6.21 and 6.59 moles per liter

Part c

Since the confidence interval not contains the value 7 we reject the hypothesis that the true mean is equal to 7. And the same result was obtained with the t test for the true mean.

6 0
3 years ago
34.1 mg NaCl in 117.3 mL of solution
Solnce55 [7]

The molarity of the solution will be 4.97 M.

<h3>What is molarity?</h3>

It is the number of moles of solutes per 1 liter of solvent or solution.

Mole of 34.1 g NaCl = 34.1/58.44 = 0.5835 mol

117.3 mL = 117.3/1000 = 0.1173 L

Molarity of the solution = 0.5835/0.1173 = 4.97 M

More on molarity can be found here: brainly.com/question/2817451

#SPJ1

6 0
2 years ago
The block in this illustration is floating in water, which has a density of 1.00 g/cm3 .What is a good estimate of the density o
miss Akunina [59]

Answer : The density of the block is estimated to be, 0.30g/cm^3.

Explanation :

Density of the water, \rho_w=1.0 g/cm^3

As we know that,

Buoyant force = \rho\times volume\times g

where,

g = gravitational acceleration

volume of the block = v

density of the block = \rho_o

Weight of the Block = Buoyant force exerted by water

\rho_o\times v\times g=\rho_w\times 30\%\text{ of volume of block}\times g

\rho_o\times v\times g=\rho_w\times 0.30v\times g

\rho_o\times v\times 9.8 m/s^2=1 g/cm^3\times 0.30v\times 9.8 m/s^2

\rho_o=0.30 g/cm^3

Thus, the density of the block is estimated to be, 0.30g/cm^3.

6 0
3 years ago
1)The average lethal dose of Valium is 1.52 mg/kg of body weight. Estimate how many grams of Valium would be lethal for a 200.-l
oksano4ka [1.4K]

Answer:

1. 0.138g of valium would be lethel in the woman

2. 125mg/min is the drip of the patient

Explanation:

1. In a body, an amount of Valium > 1.52mg / kg of body weight would be lethal.

A person that weighs 200lb requires:

200<u>lb</u> × (453.6<u>g</u> / <u>1lb</u>) × (1kg / 1000<u>g</u>) = <em>90.72kg (Weight of the woman in kg)</em>

90.72kg × (1.52mg / kg) =

137.9mg ≡

<h3>0.138g of valium would be lethel in the woman</h3>

2. The IV contains 1.5g = 1500mg/mL.

If the patient is receiving 5.0mL/h, its rate in mg/h is:

5.0<u>mL</u>/h × (1500mg/<u>mL</u>) = 7500mg/h

Now as 1h = 60min:

7500mg/<u>h</u> × (1<u>h</u> / 60min) =

<h3>125mg/min is the drip of the patient</h3>
7 0
3 years ago
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