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4 years ago

A temperature of 50.0 degrees Celsius is the same as a Kelvin temperature of approximately

Physics

1 answer:

Mila [183]4 years ago

4 0

The answer is 323 K.

Explanation:

The Celsius temperature scale is equal to - 273.15.

One kelvin is equal to the change of thermodynamic temperature that results in a change of thermal energy kT by 1.380649 * 10^−23 J.

Convert degrees Celsius to kelvins with this simple formula:

kelvins = [degree C] + 273.15

The formula to convert Celsius to kelvins is degree C + 273.15.

50 degree celsius = 50 + 273.15

= 323.15 = 323 K.

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Answer:

Explanation:

the weight of the telescope decreases because the moon attract the body with less force as compared to earth due to less gravity as compared to earth

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3 years ago

if you look inside the bowl of a shiny metal spoon, your image is upside down. if you look at the outside of the bowl, your imag

vladimir2022 [97]

Because one side of the spoon is convex and the other side is concave, the spoon’s different sides reflect differently.

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3 years ago

A gymnast does a one-arm handstand. The humerus, which is the upper arm bone between the elbow and the shoulder joint, may be ap

igor_vitrenko [27]

Answer:

$= 5.241 \times 10^{-5} m$

Explanation:

Given:

Length of cylinder is, L = 0.27 m

Outer radius of cylinder is, r_out = 1.12×10^{-2} m

Inner radius of cylinder is, r_in = 3.9×10^{-3} m

Mass of person, m = 60 kg

Young's modulus , Y = 9.4×10^9 N/m2

(a)

Compressional strain of humerous is,

$Strain = \frac{Stress}{Young's\ modulus}$

$\frac{\Delta L}{L_0} = \frac{\frac{F}{A}}{Y}$

$= \frac{(mg)}{\pi(r_out^2 - r_in^2 )Y}$

$= \frac{(60 kg)(9.8 m/s2 )}{(\pi)[( 1.12\times 10^{-2})^2 - (3.9\times 10^{-3} m)^2] (9.4\times 10^9 N/m2 )}[tex] [tex]= 1.80\times 10^{-4} m$

(b) Let assume that humerous is compressed by ΔL

Since, strain = ΔL/L0

$(1.80 \times 10^{-4} m) = ΔL / 0.29 m$

Thus,

$ΔL = (4.56 \times 10^{-4} m)(0.29 m)$

$= 5.241 \times 10^{-5} m$

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3 years ago

The relationship among speed, distance, and time is

alexdok [17]

Distance= speed (multiplied by) time

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3 years ago

Read 2 more answers

Akeem is walking on the beach on a hot summer day.

creativ13 [48]

Answer:

Sand in a beach is warmer than the water of the sea.

Explanation:

Water absorbs less heat from the sun when compared with sand. Sand is darker and also is less reflective. Because of its darker nature, absorption of heat from the sun will be more. Due to its less reflective nature the sand wouldn’t be able to reflect off the sunlight.

But water is highly reflective and can reflect off a major portion of the sunlight falling on the sea. The sea is also deep and thus the heat spreads through a large volume unlike in the case of sand. Water also has the nature of constant movement unlike sand which is stable.

This factor also heats up sand more than water. 

8 0

3 years ago