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oee [108]
3 years ago
7

Ultraviolet light with a frequency of 3.00x10^15 Hz strikes a metal surface and ejects electrons that have a maximum kinetic ene

rgy of 6.1 eV. What is the work function (in eV) of the metal ? (h = 6.63x10^-34 J.s and 1 ev = 1.60x10^-19J)
Physics
1 answer:
oksian1 [2.3K]3 years ago
3 0

Answer:

Explanation:

Frequency of 3 x 10¹⁵ ,  wavelength = 3 x 10⁸/3 x 10¹⁵ = 10⁻⁷ m = 1000A.

Energy in eV = 12375/1000 = 12.375 eV.

Maximum kinetic energy of ejected electrons = 6.1 eV

Work function = 12.375 - 6.1 = 6.275 eV.

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A carpenter builds an exterior house wall with a layer of wood 3.0 cm thick on the outside and a layer of Styrofoam insulation 2
Leno4ka [110]

Answer:

A. T=15.54 °C

B. Q/A= 0.119 W/m2

Explanation:

To solve this problem we need to use the Fourier's law for thermal conduction:

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Here, the rate of flow per square meter must be the same through the complete wall. Therefore, we can use it to find the temperature at the plane where the wood meets the Styrofoam as follows:

\frac{Q}{A} =\frac{T_1-T_0}{d_w}k_w=\frac{T_2-T_1}{d_s}k_s\\T_1(\frac{k_w}{d_w}+\frac{k_s}{d_s})=T_2\frac{k_s}{d_s}+T_0\frac{k_w}{d_w}\\T_1=\frac{T_2\frac{k_s}{d_s}+T_0\frac{k_w}{d_w}}{\frac{k_w}{d_w}+\frac{k_s}{d_s}}\\T_1= 15.54 \°C

Then, to find the rate of heat flow per square meter, we have:

\frac{Q}{A}=\frac{T_1-T_0}{d_w}k_w=0.119 \frac{W}{m^2}\\\frac{Q}{A}=\frac{T_2-T_1}{d_s}k_s= 0.119 \frac{W}{m^2}

T_0: Temperature \ in \ the \ house\\T_1: Temperature \ at \ the \ plane \ between \ wood \ and \ styrofoam\\T_2: Temperature \ outside\\k_w: k \ for \ wood\\d_w: wood \ thickness\\k_s: k \ for \ styrofoam\\d_s: styrofoam \ thickness

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3 years ago
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n200080 [17]

Answer:

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