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2 answers:
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Yes
Explanation:
From the graph, we can deduce that the wavelength changes with the speed of the wave.
This is a simple linear graph. A linear graph has a steady gradient and it shows two variables that increases proportionately.
Using the graph, we can establish that as the wavelength of the wave increases the time taken for one wave to pass through increases.
The speed of a wave is given as:
V = fλ
f is the frequency of the wave i.e the number of waves that passes through a point per unit of time
λ is the wavelength of the wave
The vertical axis on the graph shows the time for 1 wave trip, this is the wave period, T
f =
Therefore;
speed of the wave =
This can be evaluated by solving slope of the graph and finding the inverse.
We can see that as the speed of the wave changes, the wavelength will change.
learn more:
Wavelength brainly.com/question/6352445
#learnwithBrainly
Answer:
C = 2.9 10⁻⁵ F = 29 μF
Explanation:
In this exercise we must use that the voltage is
V = i X
i = V/X
where X is the impedance of the system
in this case they ask us to treat the system as an RLC circuit in this case therefore the impedance is
X =
tells us to take inductance L = 0.
The angular velocity is
w = 2π f
the current is required to be half the current at high frequency.
Let's analyze the situation at high frequency (high angular velocity) the capacitive impedance is very small
→0 when w → ∞
therefore in this frequency regime
X₀ =
the very small fraction for which we can despise it
X₀ = R
to halve the current at f = 200 H, from equation 1 we obtain
X = 2X₀
let's write the two equations of inductance
X₀ = R w → ∞
X= 2X₀ = w = 2π 200
we solve the system
2R = \sqrt{R^2 +( \frac{1}{wC} )^2 }
4 R² = R² + 1 / (wC) ²
1 / (wC) ² = 3 R²
w C =
C =
let's calculate
C =
C = 2.9 10⁻⁵ F
C = 29 μF