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xeze [42]
3 years ago
9

46 points :)

Physics
2 answers:
azamat3 years ago
5 0

Answer:

D

Amount of material that has not decayed

Explanation:

Just took the test on ed2020

IgorC [24]3 years ago
3 0

Answer:

Its is dividing by 2

Explanation:

It starts with 100 them it goes to 50, 25, 12.5 so its a cycle of dividing by 2

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A car of mass 1000kg is travelling in an eastward ( x) direction with a constant speed of 20m/s. It then hits a stationary truck
Aleonysh [2.5K]

Answer:

4.33 m/s, 5 m/s

Explanation:

mass of car, m = 1000 kg

initial velocity of car, u = 20 m/s along east

mass of truck, M = 2 x mass of car = 2000 kg

initial velocity of truck, U = 0 m/s

After collision, the velocity of car is v and the direction is 30° North of east.

The velocity of truck is V and the direction is 60° South of east.

Use conservation of momentum along X axis.

m x u = m x v x Cos 30 + M x V x Cos 60

1000 x 20 = 1000 x v x 0.866 + 2000 x V x 0.5

20 = 0.866 v + V   .... (1)

Use conservation of momentum along y axis

0 = m x v x Sin 30 - M x V x Sin 60

0 = 1000 x v x 0.5 - 2000 x V x 0.866

v = 3.464 V    ..... (2)

Substitute the value of v in equation (1)

20 = 0.866 x 3.464 V + V

V = 5 m/s

v = 0.866 x 5 = 4.33 m/s

Thus, the final speed of car is 4.33 m/s and the final speed of truck is 5 m/s after the collision.

8 0
3 years ago
The charge of an electron is -1.60x10-19 C. A current of 1 A flows in a wire carried by electrons. How many electrons pass throu
faltersainse [42]

Answer: 6.241\times 10^{18} electrons pass through a cross section of the wire each second.

Explanation:

According to mole concept:

1 mole of an atom contains 6.022\times 10^{23} number of particles.

Given : Charge on 1 electron = 1.6\times 10^{-19}C

Charge on 1 mole of electrons = 1.6\times 10^{-19}\times 6.022\times 10^{23}=96500C

To calculate the charge passed we use the equation:

I=\frac{q}{t}

where,

I = current passed = 1 A

q = total charge = ?

t = time required = 1 sec

Putting values in above equation, we get:

1A=\frac{q}{1s}\\\\q=1A\times 1s=1C

When 96500C of electricity is passed , the electrons passed = 6.022\times 10^{23}

1 C of electricity is passed , the electrons passed = \frac{6.022\times 10^{23}}{96500}\times 1C=6.241\times 10^{18}

Hence, 6.241\times 10^{18} electrons pass through a cross section of the wire each second.

4 0
3 years ago
In the experiment shown below, which is greater, the force of gravity on the pith balls (Fg) or the electrostatic force between
Oliga [24]

Answer: Fg < Fq

Explanation: just took the lab test edge 2020

8 0
3 years ago
Read 2 more answers
These are a musician favorite vegetable
kicyunya [14]
It is definitely an apple. I would know because i am a musician
5 0
3 years ago
Read 2 more answers
A girl lifts a 160-N load to a height of 1 min 0.5 s. How much power is used to lift the load?
Aleonysh [2.5K]

Answer: 320 W

Explanation:

P = W/t

W = F * d

F = 160 N

d = 1 m

t = 0.5 s

W = 160 * 1

W = 160 J

P = 160 J / 0.5 s

P = 320 W

8 0
3 years ago
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