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liq [111]
3 years ago
5

How much heat, in kJ, is required to melt 54.0 g of ice at 0°C into water at 0°C if Hfus for water = 6.01?

Chemistry
2 answers:
FrozenT [24]3 years ago
7 0

18 that is what i think it is

kati45 [8]3 years ago
3 0
The heat of fusion of 1 mole of water is 6.01 kJ/mol
1 mole of water is equal to 18 g
Therefore; 54,0 g of water is equivalent to 54/18 = 3 moles of water
Hence heat required;
 = 3 × 6.01 = 18.03 kJ
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artcher [175]

Answer:

The answer to your question is 24.325

Explanation:

Data

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Process

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Magnesium-25  Abundance = 10.13/100 = 0.1013

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2.- Write an equation

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