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liq [111]
3 years ago
5

How much heat, in kJ, is required to melt 54.0 g of ice at 0°C into water at 0°C if Hfus for water = 6.01?

Chemistry
2 answers:
FrozenT [24]3 years ago
7 0

18 that is what i think it is

kati45 [8]3 years ago
3 0
The heat of fusion of 1 mole of water is 6.01 kJ/mol
1 mole of water is equal to 18 g
Therefore; 54,0 g of water is equivalent to 54/18 = 3 moles of water
Hence heat required;
 = 3 × 6.01 = 18.03 kJ
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How many carbon atoms are there in a diamond (pure carbon) with a mass of 55 mg ?
kari74 [83]
1 mol of Carbon = 12 grams.
x mol of Carbon = 55 grams

12*x = 1 * 55
x = 55/12
x = 4.583333 mols of carbon

1 mol of anything is 6.02 * 10^23 atoms
4.58333333 mol = x

1/4.5833333 = 6.02 * 10^23/x
x = 4.58333* 6.02*10^23
x = 2.7591 * 10^23 Carbon atoms
3 0
3 years ago
Jenny wants to test the electrical conductivity of two substances dissolved in water. She is preparing the containers for the ex
katen-ka-za [31]

Answer:

Volume of the solutions

This is the most important factor for her to control.

3 0
3 years ago
An excited ozone molecule, O3*, in the atmosphere can undergo one of the following reactions,O3* → O3 (1) fluorescenceO3* → O +
Maurinko [17]

Answer:

The simplified expression for the fraction  is  \text {X} =    \dfrac{  {k_3  \times cM} }{k_1 +k_2 + k_3 }

Explanation:

From the given information:

O3* → O3                   (1)    fluorescence

O + O2                      (2)    decomposition

O3* + M → O3 + M    (3)     deactivation

The rate of fluorescence = rate of constant (k₁) × Concentration of reactant (cO)

The rate of decomposition is = k₂ × cO

The rate of deactivation = k₃ × cO × cM

where cM is the concentration of the inert molecule

The fraction (X) of ozone molecules undergoing deactivation in terms of the rate constants can be expressed by using the formula:

\text {X} =    \dfrac{ \text {rate of deactivation} }{ \text {(rate of fluorescence) +(rate of decomposition) + (rate of deactivation) }  } }

\text {X} =    \dfrac{  {k_3 \times cO \times cM} }{  {(k_1 \times cO) +(k_2 \times cO) + (k_3 \times cO \times cM) }  }

\text {X} =    \dfrac{  {k_3 \times cO \times cM} }{cO (k_1 +k_2 + k_3  \times cM) }

\text {X} =    \dfrac{  {k_3  \times cM} }{k_1 +k_2 + k_3  }    since  cM is the concentration of the inert molecule

7 0
3 years ago
How does the appearance of a substance change when it<br> changes phase?
kicyunya [14]

Answer:

Melting: the substance changes back from the solid to the liquid. Condensation: the substance changes from a gas to a liquid. Vaporization: the substance changes from a liquid to a gas. Sublimation: the substance changes directly from a solid to a gas without going through the liquid phase.

Explanation:

6 0
3 years ago
What type of element is most abundant: metals, nonmetals, or metalloids?
AnnyKZ [126]
Metals are the most abundant
7 0
4 years ago
Read 2 more answers
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