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3 years ago

Which of the following is an example of using creativity while recording measurements during an experiment?

Chemistry

2 answers:

Oksanka [162]3 years ago

5 0

I’d have to go with B

kipiarov [429]3 years ago

5 0

Answer: Option 'B' is correct.

Explanation:

Organzing data in tables is an example of using creativity while recording measurements during an experiment.

While recording measurements , if we arrange data in table it makes it more clear and feasible during an experiment.

Hence, Option 'B' is correct.

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Which of the following is the correct balanced equation for the reaction in which methane (CH4) burns in atmospheric oxygen (0₂)

Talja [164]

Answer: $\text{CH}_{4}+2\text{O}_{2} \longrightarrow \text{CO}_{2}+2\text{H}_{2}\text{O}$

Explanation:

The unbalanced equation is

$\text{CH}_{4}+\text{O}_{2} \longrightarrow \text{CO}_{2}+\text{H}_{2}\text{O}$

Balancing this equation, we get:

$\boxed{\text{CH}_{4}+2\text{O}_{2} \longrightarrow \text{CO}_{2}+2\text{H}_{2}\text{O}}$

8 0

1 year ago

What are a physical properties?

pychu [463]

Physical properties include: appearance, texture, color, boiling point, melting point, ect.

7 0

3 years ago

A sample of methane at a pressure of 1.00 atm and a temperature of 93.1 K is heated at constant pressure to a temperature of 158

Zinaida [17]

Answer:

b. The final state of the substance is a gas.

d. The sample is initially a liquid. One or more phase changes will occur.

Explanation:

Methane has the following properties:

Normal melting point: 90.7 K
Normal boiling point: 111.65 K

*"Normal" refers to normal pressure (1 atm).

According to this, we can affirm:

Below 90.7 K, methane is solid.
Between 90.7 K and 111.65 K, methane is liquid.
Above 111.65 K, methane is gas.

A sample of methane at a pressure of 1.00 atm and a temperature of 93.1 K is heated at constant pressure to a temperature of 158 K. Which of the following are true? Choose all that apply.

a. The liquid initially present will solidify. FALSE. The liquid will vaporize.

b. The final state of the substance is a gas. TRUE.

c. The sample is initially a solid. FALSE. The sample is initially a liquid.

d. The sample is initially a liquid. One or more phase changes will occur. TRUE.

4 0

2 years ago

What is the percent composition by mass of oxygen in

KiRa [710]

What is the percent composition by mass of oxygen in magnesium oxide, MgO?

Answer: 39.7 percent

4 0

2 years ago

Calculate the molality of a solution that contains 51.2 g of naphthalene, C10H8, in 500 mL of carbon tetrachloride. The density

PtichkaEL [24]

Answer: The molality of naphthalene solution is 0.499 m

Explanation:

Density is defined as the ratio of mass and volume of a substance.

$\text{Density}=\frac{\text{Mass}}{\text{Volume}}$ ......(1)

Given values:

Volume of carbon tetrachloride = 500 mL

Density of carbon tetrachloride = 1.60 g/mL

Putting values in equation 1, we get:

$\text{Mass of carbon tetrachloride}=(1.60g/mL\times 500mL)=800g$

Molality is defined as the amount of solute expressed in the number of moles present per kilogram of solvent. The units of molarity are mol/kg. The formula used to calculate molarity:

$\text{Molality of solution}=\frac{\text{Given mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent (in g)}}$ .....(2)

Given values:

Given mass of naphthalene = 51.2 g

Molar mass of naphthalene = 128.17 g/mol

Mass of solvent = 800 g

Putting values in equation 2, we get:

$\text{Molality of naphthalene}=\frac{51.2\times 1000}{128.17\times 800}\\\\\text{Molality of naphthalene}=0.499m$

Hence, the molality of naphthalene solution is 0.499 m

4 0

2 years ago